Question

What are the vertical asymptotes of R(x) =
3x - 3
______ ?
x^2 - 4
A)
x = 0
B)
x = 1, and x = -1
C)
x = 2, and x = -2
D)
x = 3, and x = -3

Answer 1

what values of x make the denominator zero, they are vertical asymptotes

so you need to factor the quadratic denominator and then solve for x.

Answer 2

You should recognise the denominator is the difference of 2 squares.

Answer 3

@Michele_Laino

Answer 4

the vertical asymptotes are located at points \(x\), such that the denominator is zero, namely:
\(x^2-4=0\)
so we have to solve this equation:
\[\huge {x^2} - 4 = 0\]

Answer 5

hint: I can rewrite such equation as follows:
\[\huge \left( {x - 2} \right)\left( {x + 2} \right) = 0\]
now, please apply the product cancellation law, in order to write the solutions of the above equation

Answer 6

@Anaise

Answer 7

stil confused @Michele_Laino

Answer 8

long time no see, rip van pelt ;p

Answer 9

huh @Anaise can u help me

Answer 10

please solve this equations:
\(x+2=0\), what is \(x\) ?

Answer 11

equation*

Answer 12

-2

Answer 13

that's right! Our first asymptote has this equation: \(x=-2\)
Now, please solve this equation:
\(x-2=0\), what is \(x\) ?

Answer 14

so the answer is C

Answer 15

that's right!