Find the value of dy/dx from the 1st eqn , substitute in the second.
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OpenStudy (theslytherinhelper):
This is probably a really silly question, but where did the (dy/dx)^2 come from?
OpenStudy (theslytherinhelper):
The only part that I'm getting from the second derivative is the 10 + 12y^2. Am I meant to add the first derivative?
OpenStudy (theslytherinhelper):
I solved and got -5x/2y^3
OpenStudy (trojanpoem):
10x + 4y^3 * dy/dx = 0
when differentiating this, it's the same as the product of two functions
y * dy/dx -> derivative of y = dy/dx = (dy/dx)^2
when you derive the first derivative you get the second one
dy/dx = dy2/d2x