Implicit Differentiation
I'm trying to understand, so I put the derivative of y^4 in my calculator and it keeps giving me zero?
I have 10x + ___ = 0
5x^2 + y^4 = -9 10x + 4y^3 * dy/dx = 0 10 + 12y^2 * (dy/dx)^2 + 4y^3 * d2y/dx2 = 0
Find the value of dy/dx from the 1st eqn , substitute in the second.
This is probably a really silly question, but where did the (dy/dx)^2 come from?
The only part that I'm getting from the second derivative is the 10 + 12y^2. Am I meant to add the first derivative?
I solved and got -5x/2y^3
10x + 4y^3 * dy/dx = 0 when differentiating this, it's the same as the product of two functions y * dy/dx -> derivative of y = dy/dx = (dy/dx)^2 when you derive the first derivative you get the second one dy/dx = dy2/d2x
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