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Mathematics 7 Online
OpenStudy (iwanttogotostanford):

PLZ HELP ASAP: What is the equation of the following graph in vertex form?

OpenStudy (iwanttogotostanford):

OpenStudy (iwanttogotostanford):

choices: y = (x − 4)2 − 4 y = (x + 4)2 − 4 y = (x + 2)2 + 6 y = (x + 2)2 + 12

OpenStudy (iwanttogotostanford):

@pooja195 @satellite73 @xo_just4me_xo @Landon34 @Kitten_is_back

OpenStudy (landon34):

yeah?

OpenStudy (iwanttogotostanford):

@radar @Teddyiswatshecallsme @Cardinal_Carlo @jhonyy9

OpenStudy (anonymous):

The vertex form of a quadratic is given by y = a(x – h)2 + k, where (h, k) is the vertex, and the "a" in the vertex form is the same "a" as in y = ax2 + bx + c. In our case, the vertex seems to be (4, -4). So: \[\left( h, k \right) = \left( 4, -4 \right)\] So far we have: \[y = a \left( x - 4 \right)^{2} + \left( -4 \right)\] @iwanttogotostanford can you think of a way to get the a-value? Hint: Since the curve resembles a smiley face, the a-value is a positive integer. \[a = ~ ?\]

OpenStudy (iwanttogotostanford):

I'm thinking 4

OpenStudy (anonymous):

Well take a look at each of your four choices @iwanttogotostanford. Which one closely resembles the equation we have?

OpenStudy (anonymous):

Hint: The a-value is positive 1 across all four choices.

OpenStudy (iwanttogotostanford):

2 then @Cardinal_Carlo

OpenStudy (iwanttogotostanford):

WAIT NO its A!!! @Cardinal_Carlo

OpenStudy (anonymous):

Exactly. Took you long enough @iwanttogotostanford ^_^

OpenStudy (iwanttogotostanford):

very true haha! Can i tag you in one more question>?

OpenStudy (anonymous):

Sure go ahead

OpenStudy (iwanttogotostanford):

ok can i post it here

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