Please i need some help

Question

anonymous · Answer

attachment

astrophysics · Answer

Try to limit 1 question per post

astrophysics · Answer

$$y=\frac{ 4x^2+12x }{ x^2+x-6 }$$ so lets do this one

anonymous · Answer

#6? ok

astrophysics · Answer

Vertical asymptotes are where the function is undefined so solve for the denominator $$x^2-x-6$$

astrophysics · Answer

Simply factor the expression and it will give you your VA

anonymous · Answer

okay i got -2 and 3

astrophysics · Answer

It's x^2+x-6 not x^2-x-6 oops

astrophysics · Answer

So it's the other way around, x = 2 and x = -3

anonymous · Answer

its either C or B but how do you tell a difference

astrophysics · Answer

What are you solving for when you factor, it's in the post befor elol

anonymous · Answer

I want to say that C is the correct one

anonymous · Answer

If your expression is x equal to a number, it is a vertical line since the x value is fixed while the y value can be anything. If it's y equals a number, it is a horizontal line. B is giving two vertical lines while C is giving two horizontal lines.

Also, to find the asymptotes you set the denominator equal to zero and solve, so your equations would come out like this:
x^2+x-6=0
(x-2)(x+3)=0
x=2 and x=3 are the equations of your asymptotes.

anonymous · Answer

So it was B thank you