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A certain reaction produces 20.7 L of gas at 1.00 atm of constant pressure. If 1350 J of heat is absorbed by the reaction what is the change in internal energy (ΔU)?
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I know that delta U = q+w and w=-p delta v
It's straight forward if you can assign signs (negative/positive) to the values. is work done or by the system? is heat absorbed or released?
delta u = 1350 J - 20.7 = 1329.3, but this is the wrong answer
the correct answer is -747J
it has to do with the units, you gotta convert the pressure, L*atm is not equal to J
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divide the work by (9.8692*10^-3)
oh i got it now!
awesome
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