Question

Find the gradient of the normal to the curve y=x^2(x^2-9/x) at the point (2,-2)
Just to double check my answer @jim_thompson5910

Answer 1

the equation is this right?

\[\Large y = x^2\left(\frac{x^2-9}{x}\right)\]

Answer 2

no it should be\[y=x^2(x^2-\frac{ 9 }{ x })\]

Answer 3

thanks

Answer 4

yw

Answer 5

what answer did you get?

Answer 6

\[-\frac{ 1 }{ 23 }\]

Answer 7

I'm getting 23 as the slope of the tangent line at (2,-2)

so yes, the slope of the normal line is -1/23

Answer 8

Thank you @jim_thompson5910 :)

Answer 9

you're welcome