If U = {1,2,3,4,5,6,7,8,9, l0} and
A = {1,2,3}
B = {2,4,6,8}
C = {7,8,9,10}
Find the following:
a. A′
b. (A U B)
c. (A′ ∩ B)′
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OpenStudy (unklerhaukus):
A', is the set of all element in the universal set U, but not in the set A.
OpenStudy (unklerhaukus):
A∪B, is the set of all elements in either A or B.
OpenStudy (anonymous):
What would the answers be? Is A' = 1,2,3,4,5,6,7,8,9,10?
OpenStudy (unklerhaukus):
no, 1,2,3 are in A
OpenStudy (anonymous):
oh wait, it would be 4,5,6,7,8,9,10
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OpenStudy (unklerhaukus):
that's better.
OpenStudy (anonymous):
So (AUB) = 1,2,3,4,6,8?
OpenStudy (unklerhaukus):
yep
OpenStudy (unklerhaukus):
Now for the last one
(A′ ∩ B), is the set all elements in both A' and B.
(A′ ∩ B)′, is the set of all elements in the universal set U, but not in (A′ ∩ B).
OpenStudy (anonymous):
So (A' and B') = 123?
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OpenStudy (unklerhaukus):
find (A′ ∩ B) first
OpenStudy (unklerhaukus):
there should not be any `B'`
OpenStudy (anonymous):
(a' union b) is {2,4,5,6,7,8,9,10)
OpenStudy (unklerhaukus):
\(\cap\) is the intersection, (not the union)
OpenStudy (anonymous):
whats the answer for the last one?
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OpenStudy (unklerhaukus):
(A′ ∩ B)
= {4,5,6,7,8,9,10} ∩ {2,4,6,8}
=
OpenStudy (anonymous):
So (a' intersection b)' = 4,6,8
OpenStudy (unklerhaukus):
No,
(A′ ∩ B) = {4,6,8}
Now find
(A′ ∩ B)′
OpenStudy (anonymous):
how do I find that?
OpenStudy (unklerhaukus):
(A′ ∩ B)′
= U \ (A′ ∩ B)
= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} \ {4, 6, 8}
(where \ is setminus)
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OpenStudy (anonymous):
so that's that answer?
OpenStudy (unklerhaukus):
no, simplify
OpenStudy (unklerhaukus):
take the elements 4,6,8, from the universal set
OpenStudy (anonymous):
then what
OpenStudy (unklerhaukus):
then you will have the answer to c.
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OpenStudy (anonymous):
so its (1,2,3,5,7,9,10) / (4,6,8)?
OpenStudy (unklerhaukus):
perform the setminus operation
OpenStudy (anonymous):
can you just give me the answer? I don't understand.
OpenStudy (unklerhaukus):
for example
{0, 15, 18, 100, 458} \ {18,100}
= {0, 15, 458}
OpenStudy (anonymous):
so its 1, 2, 3, 5, 7, 9,10?
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OpenStudy (unklerhaukus):
that's right.
but don't forget to write the braces around the elements of a set
(A′ ∩ B)′ = {1, 2, 3, 5, 7, 9, 10}