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Mathematics 4 Online
OpenStudy (anonymous):

If U = {1,2,3,4,5,6,7,8,9, l0} and A = {1,2,3} B = {2,4,6,8} C = {7,8,9,10} Find the following: a. A′ b. (A U B) c. (A′ ∩ B)′

OpenStudy (unklerhaukus):

A', is the set of all element in the universal set U, but not in the set A.

OpenStudy (unklerhaukus):

A∪B, is the set of all elements in either A or B.

OpenStudy (anonymous):

What would the answers be? Is A' = 1,2,3,4,5,6,7,8,9,10?

OpenStudy (unklerhaukus):

no, 1,2,3 are in A

OpenStudy (anonymous):

oh wait, it would be 4,5,6,7,8,9,10

OpenStudy (unklerhaukus):

that's better.

OpenStudy (anonymous):

So (AUB) = 1,2,3,4,6,8?

OpenStudy (unklerhaukus):

yep

OpenStudy (unklerhaukus):

Now for the last one (A′ ∩ B), is the set all elements in both A' and B. (A′ ∩ B)′, is the set of all elements in the universal set U, but not in (A′ ∩ B).

OpenStudy (anonymous):

So (A' and B') = 123?

OpenStudy (unklerhaukus):

find (A′ ∩ B) first

OpenStudy (unklerhaukus):

there should not be any `B'`

OpenStudy (anonymous):

(a' union b) is {2,4,5,6,7,8,9,10)

OpenStudy (unklerhaukus):

\(\cap\) is the intersection, (not the union)

OpenStudy (anonymous):

whats the answer for the last one?

OpenStudy (unklerhaukus):

(A′ ∩ B) = {4,5,6,7,8,9,10} ∩ {2,4,6,8} =

OpenStudy (anonymous):

So (a' intersection b)' = 4,6,8

OpenStudy (unklerhaukus):

No, (A′ ∩ B) = {4,6,8} Now find (A′ ∩ B)′

OpenStudy (anonymous):

how do I find that?

OpenStudy (unklerhaukus):

(A′ ∩ B)′ = U \ (A′ ∩ B) = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} \ {4, 6, 8} (where \ is setminus)

OpenStudy (anonymous):

so that's that answer?

OpenStudy (unklerhaukus):

no, simplify

OpenStudy (unklerhaukus):

take the elements 4,6,8, from the universal set

OpenStudy (anonymous):

then what

OpenStudy (unklerhaukus):

then you will have the answer to c.

OpenStudy (anonymous):

so its (1,2,3,5,7,9,10) / (4,6,8)?

OpenStudy (unklerhaukus):

perform the setminus operation

OpenStudy (anonymous):

can you just give me the answer? I don't understand.

OpenStudy (unklerhaukus):

for example {0, 15, 18, 100, 458} \ {18,100} = {0, 15, 458}

OpenStudy (anonymous):

so its 1, 2, 3, 5, 7, 9,10?

OpenStudy (unklerhaukus):

that's right. but don't forget to write the braces around the elements of a set (A′ ∩ B)′ = {1, 2, 3, 5, 7, 9, 10}

OpenStudy (anonymous):

thank you!

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