What is the simplified form of the quantity of x plus 6, all over the quantity of x plus 4 + the quantity of x minus 3, all over 3? the quantity of x squared plus 3x minus 18, all over 3 times the quantity of x plus 4 the quantity of x squared plus 4x plus 6, all over the quantity of x plus 7 the quantity of x squared plus 3x minus 18, all over the quantity x plus 7 the quantity of x squared plus 4x plus 6, all over 3 times the quantity of x plus 4
@Cardinal_Carlo I will use the equation maker this time!
\[x ^{2}+4x+6 \over 3(x+4)\]
@Cardinal_Carlo I did it haha
So you have to solve for x right?
that is my answer
yes
good job @iwanttogotostanford
thank you! I finally got it right
i thought i didn't but i did
So first open the brackets. \[ \frac{ x^2+4x+6 }{ 3x+12 }\]
Just double-checking our work: \[\frac{ x + 6 }{ x + 4 } + \frac{ x - 3 }{ 3 }\] \[\frac{3 \left( x + 6 \right) + \left( x +4 \right) \left( x - 3 \right) }{ 3\left( x + 4 \right) }\] \[\frac{ x ^{2} + 4x + 6 }{ 3x + 12 }\] Yay!
ok, thanks!
i need help studying for my math test and have a couple of questions, can i still have help?
You got this concept on lock @iwanttogotostanford. Great job!
Sure just post them up, and close this one.
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