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What are the vertical asymptotes of the function f(x) = the quantity of 2 x plus 8, all over x squared plus 5 x plus 6?
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2x+8 / x^2+5x+6
The answer choices x = −3 and x = −2 x = −3 and x = 2 x = 1 and x = −2 x = 1 and x = 2
I think its x = 1 and x = −2
Mmm, it's not your choice. Would you know how to go about finding them?
To find the vertical asymptotes, set the denominator equal to zero and solve. \[x ^{2}+5x+6=(x+3)(x+2)\] x=-2, x=-3
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That equation should be equal to zero, my mistake.
x=-2,-3 are the poles/asymptotes of the function
Oh that makes sense
so would that be the answer?
a
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mkay ty guys
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