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OpenStudy (anonymous):
k
OpenStudy (anonymous):
and medal
OpenStudy (cmtboy2):
ya
OpenStudy (cmtboy2):
OpenStudy (dangerousjesse):
Hint: like terms are terms who share the same variables.
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OpenStudy (cmtboy2):
so.. it's A,B,D
OpenStudy (cmtboy2):
right
OpenStudy (dangerousjesse):
It's A,B,C,D
OpenStudy (ktbug3):
no only one letter off try again:) d is incorrect because it has n and nsquared so it is not the same but a and b are correct
OpenStudy (ktbug3):
D IS INCORRECT i just did this in school and D is incorrect
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OpenStudy (ktbug3):
d is incorrect because when you have a regular variable and variable squared and cubed together they are not alike so n squared n and n cubed are not like terms. make sense?
OpenStudy (cmtboy2):
ok I got 4 more
OpenStudy (dangerousjesse):
Oh jeez I didn't even notice that. Great job :)
OpenStudy (cmtboy2):
OpenStudy (ktbug3):
thanks :)
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OpenStudy (cmtboy2):
OpenStudy (ktbug3):
what do you think it is
OpenStudy (cmtboy2):
b
OpenStudy (ktbug3):
i will tell you if you are correct
OpenStudy (ktbug3):
no because the first one has a n and the 2nd has an m
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OpenStudy (ktbug3):
try again
OpenStudy (cmtboy2):
um.. a
OpenStudy (anonymous):
correct
OpenStudy (ktbug3):
no there is an m and an n it is not a try c:)
OpenStudy (cmtboy2):
c
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OpenStudy (ktbug3):
yah;)
OpenStudy (cmtboy2):
OpenStudy (ktbug3):
g2g sorry bye:0) hope i helped
OpenStudy (anonymous):
This was the question, right: \[2m^2-4n^2+3m-6m^2-2m+7n^2\] That simplifies \[=2m^2-6m^2+3m-2m+7n^2-4n^2\]\[=-4m^2+m+3n^2\] Which is the answer a not c.
OpenStudy (cmtboy2):
im going with c dude im sorry
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OpenStudy (anonymous):
Just look at the calculations, it is not c.
OpenStudy (anonymous):
Please show me how you got the answer "c".
OpenStudy (cmtboy2):
ok let's do this one
OpenStudy (anonymous):
What do you think?
OpenStudy (cmtboy2):
I have no clue what this one is
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OpenStudy (anonymous):
You have the growth of each child. And you want the growth of them both together. So you need to add the individuals growths. \[5x-1+2x+3=?\]
OpenStudy (cmtboy2):
9x
OpenStudy (cmtboy2):
5x−1+2x+3=9x
OpenStudy (anonymous):
\[5x+2x=7x\]\[-1+3=2\] So \[5x+2x-1+3=?\]
OpenStudy (cmtboy2):
5x+2x-1+3=9x
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OpenStudy (anonymous):
No, it is \[5x+2x-1+3=7x+2\] You cannot add the +2 into the x's, they are not the same
OpenStudy (anonymous):
Just like you cant say 7 apples + 2 bananas = 9 apples
OpenStudy (cmtboy2):
oh sorry
OpenStudy (anonymous):
No worries
OpenStudy (cmtboy2):
I got two more
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OpenStudy (cmtboy2):
OpenStudy (anonymous):
First calculate the sum of Thomas's expression, just like we did with the last question. And then calculate Kellys expression. Now you subtract them from each other and find the difference.
OpenStudy (anonymous):
So we start with Thomas's expressions: \[3x+7+2x-3=?\]
OpenStudy (cmtboy2):
3x+7
OpenStudy (anonymous):
Yes that is the first expression he took from the bag. The second is 2x - 3. So add those together
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OpenStudy (cmtboy2):
add 3x+7 to 2x - 3
OpenStudy (anonymous):
Yes, what is that?
OpenStudy (anonymous):
\[3x+7+2x-3=?\]
OpenStudy (cmtboy2):
9x
OpenStudy (cmtboy2):
right
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OpenStudy (anonymous):
No
OpenStudy (cmtboy2):
?
OpenStudy (anonymous):
You need to keep the x's and the other numbers seperate
OpenStudy (anonymous):
You can imagine the x's as apples and the other numbers as bananas.
OpenStudy (cmtboy2):
:/
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OpenStudy (anonymous):
\[3x+2x+7-3=5x+4\]
OpenStudy (cmtboy2):
2+3=5 and 7-3=4
OpenStudy (cmtboy2):
OpenStudy (cmtboy2):
last one
OpenStudy (anonymous):
Yes
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