Medal for right answer :)))))))))))
Find the remainder of (h^4 + h^2 – 2) ÷ (h + 3)
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OpenStudy (megatronprime):
Here's what I found: H^4+h^2−2=h+3
Subtract h+3 from both sides.
h^4+h^2−2−(h+3)=h+3−(h+3)
h^4+h^2−h−5=0
Use quartic formula.
h=−1.227079,1.444794
OpenStudy (anonymous):
I HAVE 4 MORE QUESTIONS AFTER THIS ONE :) lmao
Nnesha (nnesha):
there are two ways to find remainder
1st) divide by using long or synthetic division method
2nd) solve the divisor `h+3` for the variable h and then substitute h for its value into the polynomial
OpenStudy (anonymous):
how should i write that though like whats the final answer it says type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
OpenStudy (michele_laino):
hint:
it is suffice to replace \(h=-3\) into this polynomial:
\(h^4+h^2-2\)
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OpenStudy (anonymous):
so what’s the final and complete answer :)??????????
OpenStudy (michele_laino):
please try to do this computation:
\((-3)^4+(-3)^2-2=...?\)
OpenStudy (anonymous):
88?
OpenStudy (michele_laino):
that's right!
OpenStudy (anonymous):
so thats the final answer?
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OpenStudy (michele_laino):
yes! We have applied the so called \(Theorem \;of\; Ruffini\)
OpenStudy (anonymous):
I have more questions so more medals to give
Nnesha (nnesha):
these kids should learn how to substitute numbers.
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OpenStudy (anonymous):
thx btw
OpenStudy (michele_laino):
I know how to do such division, nevertheless I have a slightly different method, since I'm italian
OpenStudy (anonymous):
cool cool so????
OpenStudy (michele_laino):
if you want I can apply my method
OpenStudy (anonymous):
yeah i just need the answer :)
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OpenStudy (michele_laino):
I'm sorry, I can't give the direct answer, since it is against the Code of Conduct
OpenStudy (anonymous):
well just make it more simple
OpenStudy (michele_laino):
ok!
first step we have to make such division: \(2x^4:x=...?\)
OpenStudy (anonymous):
2^3
OpenStudy (anonymous):
so is it 2x^3+2x^2 or just 2x?
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OpenStudy (michele_laino):
we have \(2x^3\) am I right?
OpenStudy (anonymous):
yeah?
OpenStudy (anonymous):
but the ned number? is it 2x?
OpenStudy (anonymous):
next*
OpenStudy (michele_laino):
so we can write this:
|dw:1450290685256:dw|
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OpenStudy (anonymous):
wait so whats next?
OpenStudy (michele_laino):
next we have to do this computation:
\[ - 2{x^3}\left( {x + 2} \right) = ...?\]
OpenStudy (anonymous):
is the answer 2x^3+2x^2+4
OpenStudy (michele_laino):
yes! It is
OpenStudy (anonymous):
yaws
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OpenStudy (anonymous):
wait a sec
OpenStudy (anonymous):
k so theres a triangle so 3 sides
OpenStudy (anonymous):
one side is A=2c^3+16
OpenStudy (anonymous):
b=c+2
OpenStudy (anonymous):
so what is the height or h
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OpenStudy (anonymous):
?/////????
OpenStudy (michele_laino):
we have to compute the area of such triangle, first
OpenStudy (anonymous):
Hint: The formula for area of a triangle is A = bh, where b is the length of the base and h is the height of the triangle.)
OpenStudy (michele_laino):
yes! I know, nevertheless, we have to use the Eron's formula first
OpenStudy (anonymous):
oaky
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OpenStudy (anonymous):
sry I’m pretty bad at this
OpenStudy (michele_laino):
firs step, we have to compute the half perimeter:
\(p=(a+b+c)/2=(2c^3+16+c+2+c)/2=...?\)
OpenStudy (michele_laino):
first*
OpenStudy (anonymous):
okay
OpenStudy (michele_laino):
please try to complete such computation
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OpenStudy (anonymous):
is it 2c^2-4c+8? theres also another one which ends with some more numbers
OpenStudy (anonymous):
like after 8 theres ((32/c+2))
OpenStudy (anonymous):
so which is it
OpenStudy (michele_laino):
hint:
the perimeter is:
\[\begin{gathered}
\left( {2{c^3} + 16} \right) + \left( {c + 2} \right) + c = 2{c^3} + 2c + 18 = \hfill \\
\hfill \\
= 2\left( {{c^3} + c + 9} \right) \hfill \\
\end{gathered} \]
so, what is the half-perimeter?
OpenStudy (anonymous):
I’m not sure? does the answer not start with 2c^2 is it maybe 4c^2
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OpenStudy (michele_laino):
it is not the answer it is the perimeter
OpenStudy (anonymous):
so what’s the height? I’m confused
OpenStudy (michele_laino):
as you well know, a triangle has three heights
OpenStudy (michele_laino):
is the triangle a right triangle?
OpenStudy (anonymous):
what but i know a and b so whats c
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OpenStudy (anonymous):
right?
OpenStudy (michele_laino):
like this one:
|dw:1450291781898:dw|
OpenStudy (anonymous):
the h that I’m trying to find is a 90 degree
OpenStudy (anonymous):
the one to the left
OpenStudy (michele_laino):
please can you make a drawing of the triangle?
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OpenStudy (anonymous):
yeah wait
OpenStudy (anonymous):
OpenStudy (anonymous):
there it is
OpenStudy (michele_laino):
is \(A\) an area?
OpenStudy (anonymous):
what
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OpenStudy (anonymous):
I’m trying to find h
OpenStudy (anonymous):
Find the height, h, of the triangle shown.
h = .
(Hint: The formula for area of a triangle is A = bh, where b is the length of the base and h is the height of the triangle.)
OpenStudy (michele_laino):
then we have to solve such equation:
\((c+2) \ h=2c^3+16\)
OpenStudy (anonymous):
if i give you 4 options can u tell me which on is correct
OpenStudy (michele_laino):
namely we have to find the value of \(h\):
\[h = \frac{{2{c^3} + 16}}{{c + 2}} = ...?\]
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OpenStudy (anonymous):
here are the answer options
OpenStudy (anonymous):
is it a b c or d??????????
OpenStudy (anonymous):
plzzzzzz
OpenStudy (michele_laino):
hint:
we can use this identity:
\[\begin{gathered}
2{c^3} + 16 = 2\left( {{c^3} + 8} \right) = \hfill \\
\hfill \\
= 2\left( {c + 2} \right)\left( {{c^2} - 2c + 4} \right) \hfill \\
\end{gathered} \]
so, after a substitution, we get:
\[h = \frac{{2{c^3} + 16}}{{c + 2}} = \frac{{2\left( {c + 2} \right)\left( {{c^2} - 2c + 4} \right)}}{{c + 2}} = ...?\]
OpenStudy (anonymous):
ok so the answer is 2c^2-4c+8?
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