graph the equation y-3=-3/2(x+4) Please help
\(y-y_1=m(x-x_1)\) m is the slope <---you have this given (x1,y1) is the point. <--you have this given
Do you know how to plot a point in a Cartesian graph?
no not really
Do you know what the term "slope" means?
yes
|dw:1450298177539:dw|
Does this graph look familiar to you?
yes
i need to graph the equation but i do not know how to
Do you know how to plot a point on this graph?
Yes, i'm walking you through on how tog graph on this plane.
Xy-plane
So, in your equation y-3=-3/2(x+4) What is \((x_1,y_1)\)?
yes i know how to plot a point
Okay, good. Let us determine a point from your given equation y-3=-3/2(x+4).
@Hafsahilyas1 By looking at this, \(y-y_1=m(x-x_1)\) and looking at your equation \(y-3=-\frac{3}{2}(x-(-4))\) do you see any similarities?
y1 is 3 and -3/2 is m and -4 ix x1
Perfect. Your point \((x_1,y_1)\) is \((3,-4)\). That's a point on the graph. Can you point \((3,-4)\) on this graph?|dw:1450298642273:dw|
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