Question

PLEASE HELP! MEDAL!

Answer 1

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https://answers.yahoo.com/question/index?qid=20111220211214AA6OoAz

Answer 2

By adding up the lengths of the fencing, the perimeter is:
P = 2y + (x + 3x + x) + 2y + (x + 3x + x) + 2y + 2y + 3x
(Note: the length of the base of the larger rectangle is x + 3x + x.)
= 13x + 8y.

Since the farmer has 1040 yards of fencing:
13x + 8y = 1040. . . . . . . . . . . . . . . . .(i)

The area of the entire closure is (5x)(2y) = 10xy. If we solve (i) for y, we can get the area of the closure in terms of x.

From (i):
y = (1040 - 13x)/8.

So, the area of the fence is:
A = 10xy = 5x(1040 - 13x)/4.

Differentiating dA/dx and setting dA/dx = 0 yields x = 40. Therefore, x = 40 optimizes the area of the enclosure.

I hope this helps!

Answer 3

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Answer 4

thx to you both