Question

x-3y=-6
-x+3y=6

a) the system has no solution
b) the system has a unique solution (x,y)=(_,_)
c) the system has infinitely many solutions. they must satisfy the following equation y=

Answer 1

If you have both X and Y in an equation there is no solution, so the answer would be A

Answer 2

thank you @F_Jayyy

Answer 3

I disagree....if at the end, both sides are equal, then there are infinite solutions

Answer 4

when adding these equations, you end up with 0 = 0....equal.

Answer 5

ok now im confused.. who is right ? can either of you explain how you got the answer

Answer 6

But it is not 0 because 3 would go into 6 at least twice

Answer 7

I am trying to think of a way to explain this....
x - 3y = -6
-x + 3y = 6
----------add
0 + 0 = 0
this implies infinite solutions

if it would have ended like :
0 = 3...or something unequal, then there would be no solutions

if it would have ended like :
x = 3...or y = 2...then there would be 1 solution