Can someone help me figure out how to solve this question? In 4 + In (3x)=2
Note: I have absolutely no idea how to. I completely forgot
You need to know: \(\color{#000000 }{ \displaystyle \ln(a)+\ln(b)=\ln(a\cdot b) }\) \(\color{#000000 }{ \displaystyle \ln(z) =y\quad \Longrightarrow \quad z=e^y }\)
Use the first rule to combine the logarithms on the left side.
can you explain how i should plug them in because like i said, I have absolutely no idea. This was given to me as bonus for my teacher last week and she said that i could still do it
In your case, a is 4 b is 3x
If you know; \(\color{#000000 }{ \displaystyle \ln(a)+\ln(b)=\ln(a\cdot b) }\) Then, \(\color{#000000 }{ \displaystyle \ln(4)+\ln(3x)=? }\)
so its in (4) + in(3x)=2?
"in" ?
That is ell, not i. "ln" denotes/abbreviates - natural logarithm
ln. sorry
Can you apply the [first] rule that I provided?
Im on my brothers account btw. Im in 7th grade and have absolutely no idea what ln means. Can you please explain it to me?
have you heard of a function \(e^x\) ?
yes, i have
Ok, very good
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