Can someone help me figure out how to solve this question?
In 4 + In (3x)=2
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OpenStudy (nicholausblackmon):
Note: I have absolutely no idea how to. I completely forgot
OpenStudy (solomonzelman):
You need to know:
\(\color{#000000 }{ \displaystyle \ln(a)+\ln(b)=\ln(a\cdot b) }\)
\(\color{#000000 }{ \displaystyle \ln(z) =y\quad \Longrightarrow \quad z=e^y }\)
OpenStudy (solomonzelman):
Use the first rule to combine the logarithms on the left side.
OpenStudy (nicholausblackmon):
can you explain how i should plug them in because like i said, I have absolutely no idea. This was given to me as bonus for my teacher last week and she said that i could still do it
OpenStudy (solomonzelman):
In your case,
a is 4
b is 3x
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OpenStudy (solomonzelman):
If you know;
\(\color{#000000 }{ \displaystyle \ln(a)+\ln(b)=\ln(a\cdot b) }\)
Then,
\(\color{#000000 }{ \displaystyle \ln(4)+\ln(3x)=? }\)
OpenStudy (nicholausblackmon):
so its in (4) + in(3x)=2?
OpenStudy (solomonzelman):
"in" ?
OpenStudy (solomonzelman):
That is ell, not i.
"ln" denotes/abbreviates - natural logarithm
OpenStudy (nicholausblackmon):
ln. sorry
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OpenStudy (solomonzelman):
Can you apply the [first] rule that I provided?
OpenStudy (nicholausblackmon):
Im on my brothers account btw. Im in 7th grade and have absolutely no idea what ln means. Can you please explain it to me?
OpenStudy (solomonzelman):
have you heard of a function \(e^x\) ?
OpenStudy (nicholausblackmon):
yes, i have
OpenStudy (solomonzelman):
Ok, very good
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