Will give medal, please help!!!! How do I solve (k-7)^2 +6(k-7)+10 using the quadratic formula?
I would first distribute and then combine like terms After that, we can use the quadratic formula
okay but the answer is supposed to be 4 plus or minus imaginary i
I tried using the substitution method but got a completely different answer
hmm, I'm getting that. so you substituted \(x = k -7\) and got a quadratic in \(x\).
yes
\[x^2 + 6x + 10\]did you use the quadratic formula for this?
when I substituted I got the x^2 +6x +10=0
Then used that equation in the quadratic formula
You should get \(x = -3 \pm i\). But remember that is not \(k\).
But what do you do with that -3 plus or minus imaginary i then?
You use \(x = k-7\) again.
\[\Rightarrow k-7 = -3 \pm i\]
Okay I got it thankyou
No problem. :)
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