Question

Find the measurement of MN.

Answer 1

just a sec...

Answer 2

and the choices...

Answer 3

Will medal; fan.

Answer 4

.. and follow

Answer 5

@parthKohli

Answer 6

@ganeshie8

Answer 7

@DangerousJesse

Answer 8

@Anaise

Answer 9

@umermemon9

Answer 10

we can both help each other

Answer 11

@et1231

Answer 12

plz help

Answer 13

First guess?

Answer 14

I better at art work, see? (M. C. Escher) XD

Answer 15

2.8---

Answer 16

\[\large(10x+.1)+(7x-.2)=10\]

Answer 17

... so that would be the following:(?)\[(10x+.1+.2)+(7x-.2 + .2)=10\]

Answer 18

\[\large17x-.1=10\]

Answer 19

1I'm working it out right now...

Answer 20

Add .1 to both sides \[\large17x=10.1\]

Answer 21

Okay :)

Answer 22

\[10+.1=10.1(/17=x)\]

Answer 23

No, divide: \[\large10.1\div17\]

Answer 24

Oops wait we're solving for 5.

Answer 25

\[\large(7x+.1)+(10x-.2)=5\]

Answer 26

Simplify \[\large17x-.1=5\]

Answer 27

\[\large.1+5=5.1\]

Answer 28

OK so that means that = 17x

Answer 29

\[\large5.1\div17=x\]

Answer 30

Yes, 17x=5.1 :)

Answer 31

0.3??????????

Answer 32

Yes, now substitute x with that and check the math, then you can do the math to find MN :)

Answer 33

can we work through that?

Answer 34

if not, I'm sure I can do it on my own

Answer 35

Sure thing. \[\large(10\times.3-2)+(7\times.3+.1)=\]

Answer 36

1 + (2.1 + .1) so that's about 3.1?

Answer 37

\[\large10\times.3=3\]\[\large3-.2=2.8\]

Answer 38

thank you; is that the finished equation?

Answer 39

Nope\[\large2.8+(7\times.3+.1)\]\[\large7\times.3=\]

Answer 40

2.1

Answer 41

2.1?*

Answer 42

And \[\large2.1+.1=\]

Answer 43

3.1

Answer 44

No, we're adding .1, not 1

Answer 45

2.2?

Answer 46

Yep, and is this true: \[\large2.8+2.2=5\]

Answer 47

Thanks! Wow, you really helped... just a sec for medal...

Answer 48

;)

Answer 49

So \[\large MN=2.8\] :)