What is the domain of y = tan x?
@mathmale A?
@amistre64
Remember, Spikers, that the cot x function is periodic. It repeats itself indefinitely. Pi is the period of just ONE cycle of the cot x function. If y ou were to draw y=cot x, you'd have the first cycle, of length Pi, beginning at x=0. But there'd be repetitions of the same graph on the right and on the left. So, using this info, judge which of the given answers is best. It's not Pi, by the way.
hint: since we have the subsequent definition: \[\tan x = \frac{{\sin x}}{{\cos x}}\] then tangent function is not defined at point such that: \(\cos x=0\)
points*
y is not defined for pi/2 or (3 pi) / 2 for 0 <= X <= 2 pi
b.
b is a wrong option, since \(\cos 0=1\) and \( \cos \pi=-1\)
I know this is taking a lot of time, but still strongly recommend that you graph one cycle of y=cot x before trying to proceed further.
namely tangent function exists inside \((0,1)\) except one point
sorry, very sorry. It's y=tan x we're discussing. Everyone in agreement?
oops.. I meant \((0, \pi)\)
Michele, the basic, central graph of the tangent function has the domain (-pi/2 , +pi/2), not (0, pi) (unless you're talking about the cot x function.
Michele_Laino is clearly talking about the guess the original poster made \((0,\pi\))
But we need to find the domain for multiple cycles of the tangent function. Thus, b is incorrect because that's the domain of ONLY ONE CYCLE of the cot. function.
no, please it is my explanation in order to say that option b is a wrong option @mathmale
Point made, point correct, point taken, apologies issued. :)
So, we eliminate answer choices a and b. Of the remaining two choices, which is correct, and why?
Spikers, your input, please!
I think Spikers is waiting for someone to give the answer
I do notice that Spikers has typed in a message here ONLY ONCE, and that was to state that the answer is "b" without explanation. Spikers? Time for further input from you.
Spikers, if I were you I'd do a search for "y=tan x" and look carefully at the graphs that pop up. You should eventually be able to determine the domain of a function simply by looking at the graph. That certainly works for y=tan x, if not for every other function.
sorry, I have to get off the 'Net.
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