Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

calc help

OpenStudy (anonymous):

A circle is growing so that each side is increasing at the rate of 2cm/min. How fast is the area of the circle changing at the instant the radius is 10cm? Include units in your answer.

OpenStudy (anonymous):

@Zale101

OpenStudy (zale101):

|dw:1450393944381:dw|

OpenStudy (zale101):

We know that the circle keeps increasing at a rate of 2cm/min. Meaning, the area of a circle keeps increasing.

OpenStudy (zale101):

What is the area of a circle?

OpenStudy (anonymous):

pir^2

OpenStudy (zale101):

\(A(r) =\pi r^2\) How fast is the area of a circle changing? To answer this, we need to take the derivative of the area to obtain the instantaneous value for the rate of change of the area.

OpenStudy (anonymous):

2piR(dr/dt)

OpenStudy (zale101):

Your question is asking you to find the area's rate of change.

OpenStudy (zale101):

\(\Large \frac{d(A(r))}{dt}=\frac{dA}{dt}=\frac{d}{dt}[\pi r^2]\) \(\Large \frac{dA}{dt}=2\pi r \frac{dr}{dt}\)

OpenStudy (anonymous):

ok so whats next?

OpenStudy (zale101):

You are giving the radius (r) and dr/dt (the rate of change of the radius). Plug them in the dervative of the area to get dA/dt.

OpenStudy (anonymous):

dA/dt= 2pi (10)(2)

OpenStudy (zale101):

Yes.

OpenStudy (anonymous):

So the answer is 40pi?

OpenStudy (zale101):

Yes.

OpenStudy (anonymous):

ok thanks. i have one more if you don't mind

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!