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OpenStudy (anonymous):
A circle is growing so that each side is increasing at the rate of 2cm/min. How fast is the area of the circle changing at the instant the radius is 10cm? Include units in your answer.
OpenStudy (anonymous):
@Zale101
OpenStudy (zale101):
|dw:1450393944381:dw|
OpenStudy (zale101):
We know that the circle keeps increasing at a rate of 2cm/min. Meaning, the area of a circle keeps increasing.
OpenStudy (zale101):
What is the area of a circle?
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OpenStudy (anonymous):
pir^2
OpenStudy (zale101):
\(A(r) =\pi r^2\)
How fast is the area of a circle changing? To answer this, we need to take the derivative of the area to obtain the instantaneous value for the rate of change of the area.
OpenStudy (anonymous):
2piR(dr/dt)
OpenStudy (zale101):
Your question is asking you to find the area's rate of change.
OpenStudy (zale101):
\(\Large \frac{d(A(r))}{dt}=\frac{dA}{dt}=\frac{d}{dt}[\pi r^2]\)
\(\Large \frac{dA}{dt}=2\pi r \frac{dr}{dt}\)
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OpenStudy (anonymous):
ok so whats next?
OpenStudy (zale101):
You are giving the radius (r) and dr/dt (the rate of change of the radius). Plug them in the dervative of the area to get dA/dt.
OpenStudy (anonymous):
dA/dt= 2pi (10)(2)
OpenStudy (zale101):
Yes.
OpenStudy (anonymous):
So the answer is 40pi?
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