Can some one walk me through this equation: 8= (x-3)^3/4
Step 1: Exponentiate both sides of the equation to the power of 4. This will get rid of the 1/4 power. Step 2: Root both sides to the power of 3. This will get rid of the cube power. Step 3: Add 3 to both sides. This will get simply the variable side. Step 4: By now, you should have your x-value which I assume is what you needed.
Okay give me a sec.
not to butt in, but i would take the cubed root first, before i raised to the power of 4 the numbers are much easier that way
\[8=(x-3)^{\frac{3}{4}}\iff 8^{\frac{4}{3}}=x-3\]
So I would get x= 5^3/4 right @satellite73
@Cardinal_Carlo Doing it your way I got \[x=-5\pm8i \sqrt{3}\] Was that right?
Not quite. My approach was more of a step-by-step breakdown of Satellite's approach. You should've gotten what he got.
\[8^{\frac{ 4 }{ 3 }} + 3 = x\] See?
Yeah but there is a bit of a problem and that is that none of the given answers matches that answer. @Cardinal_Carlo
If that's the case, from now on, please provide an answer list as you post your question. It makes it easier for all of us.
Oh okay, sorry for that. @Cardinal_Carlo The answers that they provided me are. 16 19 13 11
\[8^{\frac{ 4 }{ 3 }} + 3 = ~?\] The answer is actually one of the choices you put up.
Hint: Simplify the expression.
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