Mathematics
8 Online
OpenStudy (calculusxy):
MEDAL!!!
What do I do when for a solution of a parabola I don't get a real number (like 1, 3) instead I get something like:
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OpenStudy (calculusxy):
\(\huge \frac{2 \pm 2\sqrt{1} }{3}\)
OpenStudy (anonymous):
\[\sqrt1=??\]
OpenStudy (calculusxy):
fine, we can replace this to be like 3. i am making this up
OpenStudy (anonymous):
oh ok it is a hypothetical question
OpenStudy (calculusxy):
\[\frac{2 \pm 2\sqrt{1} }{3}\]
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OpenStudy (anonymous):
you get what you get
if the answer is \[\frac{2\pm\sqrt5}{2}\] then those are the two answers
OpenStudy (anonymous):
most of the time you do not get a rational number
OpenStudy (calculusxy):
so if i don't get a rational number, then i will just have to leave it like that right?
OpenStudy (anonymous):
yes
OpenStudy (calculusxy):
ok thank you.
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OpenStudy (anonymous):
you have a specific example?
OpenStudy (calculusxy):
another question.
OpenStudy (anonymous):
kk
OpenStudy (calculusxy):
so if i have (hypothetical):
\[\frac{ 4 \pm 8\sqrt{2} }{ 4 }\]
then i can simplify it as:
\[\frac{ 1 \pm \sqrt{3} }{ 1 }\] or just \(1 \pm \sqrt{3}\)
OpenStudy (anonymous):
not quite
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OpenStudy (calculusxy):
oh sorry i forgot to put the 2 in front of the square root
OpenStudy (anonymous):
\[\frac{ 4 \pm 8\sqrt{2} }{ 4 }=\frac{4}{4}\pm\frac{8\sqrt2}{4}\]
OpenStudy (anonymous):
so \[1\pm2\sqrt2\] it means you used the quadratic formula when you should have completed the square
OpenStudy (anonymous):
you have the original equation ?
OpenStudy (calculusxy):
\[1 \pm 2\sqrt{2}\]
no i just made a hypothetical question because i have a test on this topic (along with others) tmrw
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OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
good luck with your exam
OpenStudy (calculusxy):
and but if i have:
\[\frac{ 2 \pm 6\sqrt{5} }{ 3 }\]
then i just leave it as it is?
OpenStudy (anonymous):
yes
OpenStudy (calculusxy):
ok thank you so much!
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OpenStudy (anonymous):
i would
OpenStudy (anonymous):
yw
OpenStudy (anaise):
......