suppose f(x) = ax+b where a and be are constants. if f(1)=7 and f(3)=5, find a and b.
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OpenStudy (solomonzelman):
Ok, \(f(1)=7\) means that
\(\color{#000000 }{ \displaystyle f(1) = a\cdot (1)+b=7 }\)
\(\color{#000000 }{ \displaystyle a+b=7 }\)
OpenStudy (anonymous):
ok...i kinda get it
OpenStudy (solomonzelman):
plug in f(3)=5 into the function (as I did with f(1)=7)
and you will have the second equation
OpenStudy (anonymous):
ok so then it becomes \[f(3)=a(3)+b=-5\]
OpenStudy (anonymous):
am i correct or..?
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OpenStudy (solomonzelman):
-5 ?
OpenStudy (anonymous):
sorry, the f(3)=-5
OpenStudy (anonymous):
i made a typo up above
OpenStudy (solomonzelman):
I thought the 5 was positive
OpenStudy (solomonzelman):
oh, typo, ok
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OpenStudy (anonymous):
yea haha sorry. so do we leave the equations like so or do we do more with them
OpenStudy (solomonzelman):
yes, and a(3), is same thing as a•3, so you can just write
\(\color{#000000 }{ \displaystyle 3a+b=-5 }\)
OpenStudy (solomonzelman):
So you were given
f(1)=7 and f(3)=-5
and thanks to that we have the two equations below,
\(\color{#000000 }{ \displaystyle a+b=7 }\)
\(\color{#000000 }{ \displaystyle 3a+b=-5 }\)
which is just a system of equations.
OpenStudy (anonymous):
the back of my book says the answers are a=-6 and b=13
OpenStudy (solomonzelman):
and you want to know why...
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OpenStudy (solomonzelman):
*(duh)*
OpenStudy (anonymous):
yes please lol
OpenStudy (solomonzelman):
first, is it clear how we obtained the system of equations below?
\(\color{#000000 }{ \displaystyle a+b=7 }\)
\(\color{#000000 }{ \displaystyle 3a+b=-5 }\)
OpenStudy (anonymous):
yes
OpenStudy (solomonzelman):
You can subtract b on both sides of the first equation, and what wll this give you?
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OpenStudy (anonymous):
um you get \[a=7-b\]
OpenStudy (anonymous):
i think
OpenStudy (solomonzelman):
yes, and substitute this into the second equation for a
\(\color{#000000 }{ \displaystyle 3(7-b)+b=-5 }\)
OpenStudy (solomonzelman):
then expand and simplify the left side
OpenStudy (anonymous):
ok so then you get \[21-2b=-5\]
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OpenStudy (anonymous):
then subtract 21 from 5, you get -16/2b
OpenStudy (anonymous):
which is -8
OpenStudy (anonymous):
is that correct?
OpenStudy (anonymous):
for b?
OpenStudy (anonymous):
wait no i got it wrong
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OpenStudy (anonymous):
oh wait haha i see what i did wrong, ok b=13
OpenStudy (anonymous):
now that i know that, how do i get a?
OpenStudy (anonymous):
oh wait you would just subtract 7-13=-6
OpenStudy (anonymous):
ok hahaha makes so much sense now
OpenStudy (solomonzelman):
21−2b=−5
−2b=−5-21
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OpenStudy (solomonzelman):
-26
OpenStudy (solomonzelman):
not -16
OpenStudy (anonymous):
yea haha i see what i did wrong
OpenStudy (solomonzelman):
and b is?
OpenStudy (anonymous):
13
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OpenStudy (solomonzelman):
as given in answers...
OpenStudy (anonymous):
b is 13 in the back of the book...
OpenStudy (solomonzelman):
yes
OpenStudy (solomonzelman):
and then the a,
a+b=7
a+13=7
a=...
OpenStudy (anonymous):
great! ok if u dont mind me asking, how long will you be online for? a is -6
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OpenStudy (anonymous):
i just wanna know just in case i accidentally bother you lol
OpenStudy (solomonzelman):
No, it is fine... we all make simple error. But when teachers take off 10 points off for that, they are pigs !