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Physics 7 Online
OpenStudy (mtalhahassan2):

need help

OpenStudy (mtalhahassan2):

A satellite 1000.0 kg has a circular orbit that is at an altitude of 5 earth radii. 1. Calculate the orbital velocity of the satellite in its orbit. 2. Calculate the total energy of the satellite in its orbit. 3. Is the satellite bound to Earth? Explain 4. How much work is done by gravity on the satellite as it moves around Earth? Justify. 5. Using conservation of energy, how fast would be the satellite be if were to descend to an altitude of 2 Earth radii? 6. What is the orbital required of a satellite at an altitude of 2 Earth radii? If it is different from 5, how can you explain the difference between the answer 5 and 6? 7. If the satellite needs to be raised to an orbit of 10 Earth radii, how much energy needs to be supplied to the satellite if losses to thermal energy amount to 30.% of kinetic energy?

OpenStudy (mtalhahassan2):

@jigglypuff314

OpenStudy (mtalhahassan2):

@SolomonZelman

OpenStudy (mtalhahassan2):

1. v orb = sqrt GM/r = sqrt 6.67x10^-11x5.98x10^24/ 5x6.38X10^6 = 3.54x 10^3 m/s

OpenStudy (mtalhahassan2):

2. delta Et = 1/2 delta EG = m(g)delta h/ 2 = 10000x |9.81| x 4x6.35x10^5 = 1.25x10^11

OpenStudy (shamim):

Satellite has 2 equal n oposit forces

OpenStudy (shamim):

Orbiting satellite's centrifugal force=mv^2/r

OpenStudy (shamim):

Centripetal force=GMm/r^2

OpenStudy (shamim):

G=gravitational constant M=mass of earth m=mass of satellite

OpenStudy (shamim):

In equilibrium mv^2/r=GMm/r^2 Right?

OpenStudy (shamim):

So v^2=GM/r

OpenStudy (shamim):

v=Sqrt(GM/r)

OpenStudy (shamim):

r=distance frm the centre of earth to the satellite

OpenStudy (shamim):

r=altitude+radius of earth

OpenStudy (mtalhahassan2):

oh ok

OpenStudy (shamim):

Altitude = 5R Radius of earth =R

OpenStudy (shamim):

r=?

OpenStudy (mtalhahassan2):

radius of earth is 6,371 km

OpenStudy (mtalhahassan2):

Altitude = 5R

OpenStudy (shamim):

r=5R+R=6R=6*6371km Right?

OpenStudy (mtalhahassan2):

wait which part are you doing

OpenStudy (shamim):

v=?

OpenStudy (shamim):

First 1

OpenStudy (mtalhahassan2):

oh so I did it wrong

OpenStudy (shamim):

I think so

OpenStudy (shamim):

U used r=5R In ur equation

OpenStudy (mtalhahassan2):

yeah

OpenStudy (mtalhahassan2):

so the r be r=5R+R=6R=6*6371km

OpenStudy (mtalhahassan2):

are you sure na?

OpenStudy (shamim):

As i know r will b the distance frm the centre of earth to the satellite Right?

OpenStudy (shamim):

So r=?

OpenStudy (mtalhahassan2):

r=altitude+radius of earth

OpenStudy (mtalhahassan2):

Altitude = 5R, radius of earth = 6.38X10^6

OpenStudy (mtalhahassan2):

right?

OpenStudy (shamim):

Radius of earth=R=6.38*10^6m

OpenStudy (shamim):

Anyway altitude means the distance frm the surface of earth to the satellite. Right?

OpenStudy (mtalhahassan2):

are you sure we don't have to use the Altitude

OpenStudy (mtalhahassan2):

Altitude is like a hight

OpenStudy (mtalhahassan2):

the height of an object or point in relation to sea level or ground level.

OpenStudy (mtalhahassan2):

i believe the r = h+ radius of earth

OpenStudy (shamim):

Yes u r right !

OpenStudy (shamim):

Given Height=5R Radius of earth=R r=5R+R=6R

OpenStudy (mtalhahassan2):

so that's mean i did it right?

OpenStudy (shamim):

No u were wrong!

OpenStudy (shamim):

U used r=5R

OpenStudy (mtalhahassan2):

i use 5 because the altitude is 5

OpenStudy (mtalhahassan2):

radius of earth is a different number which is 6.38X10^6

OpenStudy (mtalhahassan2):

@Zale101 @AlexandervonHumboldt2 @bababababananaxo @Curry @Daniellelovee @EmogirlAtEmoooocow @They_Call_Me_Narii @FortyTheRapper @Hayhayz @izzyrawrz @bababababananaxo @Agl202 @CountryBoy15 @mayankdevnani

OpenStudy (shamim):

Need to draw it

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