Willing to pay a reasonable amount to anyone who solves this puzzle.

Good Morning!
This is Rajeev, How are you? I hope you will be fine. I am gain sending you a numeric based series puzzle for a hope of solution. If possible, please help to solve.

Importance High!!!!!!!!!!!!!!!!!

Dear Sir / Madam,

I am putting a signs series in front of you which based on real numbers from 01 to 100.
I am finding that what is the reason of behind Approx equability of signs at end of the month or year i.e. mentioned below:-

(++), (+-), (--),(-+)

Puzzle Explanation

Let's define a kind of mapping:
0↔1
2↔3
4↔5
6↔7
8↔9

(+) means: an Even number
(-) means: an Odd number

I simply say: for any EO (+-) it exists an OE (-+) which is paired to.
And that's true since each E is mapped to a O and vice versa (1 to 1 relation where "f(f(x))=x" ) !
E.g.: 29 ↔ 38

There is 25 numbers in the EO (+-) group, so 25 in OE (+-).
There is 25 numbers in the EE (++) group, so 25 in OO (--).

Picking a number at random basis between 01 and 100 inclusive is choosing equitably in EO, OE, EE or OO group. (25% for each)

So, I really need of your help to solve a puzzle please. I just am trying to make you understand what type of solution I need:

(Complete sheets for the year 2014 & 2015 are attached with this mail)

You can see that there are two series running in a day of pair make by even (+) and odd (-) signs, i.e. (++), (+-), (--) & (-+) as above said.
The total of pair combination signs become approx equal to each other at the end of the month or year and every year. So, I am sending you attachment to go through the year’s result).
By this analysis:
1- I want to know that what is the relation between current falling signs and past fell signs.
2- How can I come to know, what type of combination of sign would be any particular date or day.
3- There is surety that there is some relation between First Series of combination of signs And Second Series of combination of signs OR Between First Series of combination of signs and Second Series of combination of signs.

My Self R&D and Questions

R&D (1):- I have totalized each combinations i.e. (++), (--), (+-), (-+) separately for both series. After that I also Grand total (First Series + Second Series) of for all same signs than you can see its all are also going on approx equal

R&D (2):- I have also made 16 types of move by combination of both series (First & Second series) signs. The combinations are showing in my working sheet name by 16 moves.

R&D (3):- I have made four combinations by signs combination of both series. I have compare first sign with first sign and Second sign with second sign of both series than the FOUR combination made by this i.e. “TRUETRUE”, “FALSEFALSE”, “TRUEFALSE” & “FALSETRUE”
After that I totalize each in whole year than you can see its all are going on approx equal

Actually, I don’t understand what is choosing method of sign on each day but It’s confirmed every type of sign open within a week, month and year i.e. (++), (--), (+-), (-+).
So finally that is my question what is the method of next sign calculation on basis of became open signs two times (means one time for one series) in a day.

Please help me to how come to know what type of fall may be for next day by reviewing past or first combination of signs. So reply or elaborate me with an example.

I would be very grateful to you till entire life.

Encl: - - 2 years data sheets
- Puzzle Explanation
- 2 Help file to solve the puzzle

Note: - Last day of every month no result will be showed because it is close every last day (data audit day) of month.

Thanks & Regards

RAJEEV SHRIVASTAVA
Mail: rajeev.amit08@gmail.com

Question

Willing to pay a reasonable amount to anyone who solves this puzzle.

Good Morning!
This is Rajeev, How are you? I hope you will be fine. I am gain sending you a numeric based series puzzle for a hope of solution. If possible, please help to solve.

Importance High!!!!!!!!!!!!!!!!!

Dear Sir / Madam,
 
I am putting a signs series in front of you which based on real numbers from 01 to 100.
I am finding that what is the reason of behind Approx equability of signs at end of the month or year i.e. mentioned below:-

(++), (+-), (--),(-+) 
 
Puzzle Explanation
 
Let's define a kind of mapping: 
0↔1
2↔3
4↔5
6↔7
8↔9

(+) means: an Even number 
(-) means: an Odd number

I simply say: for any EO (+-) it exists an OE (-+) which is paired to.
And that's true since each E is mapped to a O and vice versa (1 to 1 relation where "f(f(x))=x" ) !
E.g.: 29 ↔ 38

There is 25 numbers in the EO (+-) group, so 25 in OE (+-).
There is 25 numbers in the EE (++) group, so 25 in OO (--).

Picking a number at random basis between 01 and 100 inclusive is choosing equitably in EO, OE, EE or OO group. (25% for each)
 
So, I really need of your help to solve a puzzle please. I just am trying to make you understand what type of solution I need:

(Complete sheets for the year 2014 & 2015 are attached with this mail)
 
You can see that there are two series running in a day of pair make by even (+) and odd (-) signs, i.e. (++), (+-), (--) & (-+) as above said.
The total of pair combination signs become approx equal to each other at the end of the month or year and every year. So, I am sending you attachment to go through the year’s result).
By this analysis:
1-     I want to know that what is the relation between current falling signs and past fell signs.
2-     How can I come to know, what type of combination of sign would be any particular date or day.
3-     There is surety that there is some relation between First Series of combination of signs And Second Series of combination of signs OR Between First Series of combination of signs and Second Series of combination of signs.

My Self R&D and Questions

R&D (1):- I have totalized each combinations i.e. (++), (--), (+-), (-+) separately for both series. After that I also Grand total (First Series + Second Series) of for all same signs than you can see its all are also going on approx equal

R&D (2):- I have also made 16 types of move by combination of both series (First & Second series) signs. The combinations are showing in my working sheet name by 16 moves.

R&D (3):- I have made four combinations by signs combination of both series. I have compare first sign with first sign and Second sign with second sign of both series than the FOUR combination made by this i.e. “TRUETRUE”, “FALSEFALSE”, “TRUEFALSE” & “FALSETRUE” 
After that I totalize each in whole year than you can see its all are going on approx equal

Actually, I don’t understand what is choosing method of sign on each day but It’s confirmed every type of sign open within a week, month and year i.e. (++), (--), (+-), (-+).
So finally that is my question what is the method of next sign calculation on basis of became open signs two times (means one time for one series) in a day.

Please help me to how come to know what type of fall may be for next day by reviewing past or first combination of signs. So reply or elaborate me with an example.
 
 I would be very grateful to you till entire life.

Encl: - - 2 years data sheets
         - Puzzle Explanation
         - 2 Help file to solve the puzzle

Note: - Last day of every month no result will be showed because it is close every last day (data audit day) of month.

Thanks & Regards

RAJEEV SHRIVASTAVA
Mail: rajeev.amit08@gmail.com

parthkohli · Answer

@ganeshie8 @rational

ikram002p · Answer

This is linear mapping its only x+1

ikram002p · Answer

Orr even/odd translation

ganeshie8 · Answer

@RAJEEVSHRIVASTAVA 

Looks the main post got clipped. Please post the complete problem again in a reply

parthkohli · Answer

He left soon after posting the problem :|

ikram002p · Answer

wow what a problem

anonymous · Answer

a lot

anonymous · Answer

Dear Sir, I have send a reply of foreigner regard my numeric based sign puzzle. But I am not able to understand that how can apply this on my puzzle data. So please review once if you understand. ---------- Forwarded message ---------- From: WARREN PORTER Date: Mar 13, 2012 5:56 PM Subject: Re: 4x3 knight swap puzzle To: rajeev shrivastava Cc: The first two moves are a1-c2 and c2-a3. As each square opens up a knight from the other side takes two moves to take it (except for a4-c3-a2-c1). When b1 opens, the c4 knight needs to move through a3. So the last few moves are a3-b2 c4-a3 a3-b1 b2-a3 a3-c4. In plain text the isomorph shows how the two rings of knights interact. --- On Tue, 3/13/12, rajeev shrivastava wrote: From: rajeev shrivastava Subject: Re: 4x3 knight swap puzzle To: "WARREN PORTER" Date: Tuesday, March 13, 2012, 4:12 AM Dear Sir I have not received any reply from your side. Please this to remind you only. On Fri, Mar 2, 2012 at 6:55 PM, WARREN PORTER wrote: The isomorphs will hopefully be clearer in this format. I'll provide the solution in a week unless someone solves it before then. The object is to swap the whites knight for the black ones and vice versa. There are white knights at a1, b1, and c1 while the black knights are on the 4th rank. An isomorph is helpful in solving this puzzle. Martin Gardner noted in "aha Insight" that the eight outside squares on a 3x3 board make up a closed knight's tour and his isomorph consisted of interlocking rings, but this model may be more helpful: The six shaded squares are a closed knight tour as are the unshaded squares. When unfolded into an isomorph there are two rings connected by the a2-c3 and c2-a3 links. Each of the rings contain two knights of one color and one knight of the opposite color. To solve this one knight each is swapped with the other ring while the other knights are repositioned within their original ring. Moving a knight one time counts as one move and any knight can move at any time. To solve, please start with a1-b3, a1-c2, or b1-a3. This will eliminate rotations and/or reflections in the final solution. +-----------------+ ¦·····¦¦¦¦¦¦¦·····¦··4 ¦··B··¦¦¦B¦¦¦··B··¦ +-----+-----+-----¦ ¦·····¦¦¦¦¦¦¦·····¦··3 ¦·····¦¦¦¦¦¦¦·····¦ +-----+-----+-----¦ ¦¦¦¦¦¦¦·····¦¦¦¦¦¦¦··2 ¦¦¦¦¦¦¦·····¦¦¦¦¦¦¦ +-----+-----+-----¦ ¦¦¦¦¦¦¦·····¦¦¦¦¦¦¦··1 ¦¦¦W¦¦¦··W··¦¦¦W¦¦¦ +-----------------+ ···a·····b·····c a4--c3--a2--c1 ||··||··||··|| b2··b1··b4··b3 ||··||··||··|| c4--a3--c2--a1 This puzzle appeared in "aha! Insight" by Martin Gardner in 1978 with an 18 move solution which was not revealed. Two other readers and I found a 16 move solution which Mr. Gardner discussed in his Scientific American column in early 1978 or 1979, but I lost my copy of it.

astrophysics · Answer

@dan815

anonymous · Answer

Helo Sir,
I HAVE ATTACHED THE SHEET WITH A NEW LOGIC. PLS SEE THE ATTACHED SHEET AND SEE LEFT SIDE ON TOP I HAVE TOTAL OF EVERY SIGN FOR BOTH SERIES AND TOTAL OF PAIR (EE) WITH (OO) & EO WITH OE. I HAVE FOUND THEIR TOTAL IS GOING ON VERY EQUAL. AND IN SECOND SERIES I TOOK (EE) WITH (EO) AND (OO) WITH (OE).
ALL PAIR GROUP ARE MOVING BY A TECHNIC OR PROGRAMMING. BUT I AM NOT GEETING WHAT IS FORMULA ON BEHIND THIS. SO PLS. LOOK IT AND TRY TO UNDERSTAND.

dayakar · Answer

it is like binary operation using 0.1 here + and -

those who knows data structure can give answer to your problem.

anonymous · Answer

I have already my data file in above msg. please check and reply if you do.