Question

i need help plz
will medal and fan

Answer 1

Solve 2x2 + 5x = 12

Answer 2

x= three over two and x = −4
x = 2 and x = −3
x = −6 and x = 5
x = one over two and x = one over three

Answer 3

\(\color{#000000 }{ \displaystyle 2x^2+5x-12=0 }\)

The discriminant of this equation is:
\(\color{#000000 }{ \displaystyle \Delta =5^2-4\cdot 2\cdot (-12) =25-(-96)=121 }\)

Answer 4

wow im lost even wrse now

Answer 5

\(\normalsize\color{ slate }{{\bbox[5pt, lightcyan ,border:2px solid black ]{ {\Large x=~} \huge{ \frac{-\color{magenta}{b} \pm\sqrt{ \Delta }}{2 \color{blue}{a}} =\frac{-\color{magenta}{b} \pm\sqrt{ \color{magenta}{b} ^2-4 \color{blue}{a} \color{red}{c}}}{2 \color{blue}{a}} }~ }}}\)

when the equation is \(\color{black}{ \color{blue}{a} x^2+ \color{magenta}{b}x+ \color{red}{c}=0 }\).

Answer 6

that part inside the square root is the "discriminant"

Answer 7

okay

Answer 8

I calculated this discriminant to be \(\Delta=121\),
\(121=11^2~~~~\color{grey}{\rm( perfect~square)}\)

Answer 9

And since the discriminant is a perfect square
you ARE able to factor the \(\color{#000000 }{ \displaystyle 2x^2+5x-12=0 }\).

OR, you can alternatively find the solutions for
\(x\), using the "Quadratic Formula", (in the box)
since you already know the discriminant (\(\Delta\)).

Answer 10

thnks for helpin me understand the problem a lil bit more