Question

Calculus help! *Medal**

Answer 1

I know Its NOT A

Answer 2

Like roman numeral "I" is wrong correct? which would leave the answer to be B.

Answer 3

I think.. .I just confused myself.

Answer 4

you are correct

Answer 5

I is correct.

Answer 6

Are you sure?

Answer 7

yes

Answer 8

I is false...consider \(f(x)=x^3\)

\(f'(0)=0\) but you do not have a max or min at x=0

Answer 9

i thick I and III is correct option C.

Answer 10

in lim Q ans is 1

Answer 11

use L'Hospital rule

Answer 12

for max or min f'(x)=0 and f''(x) not equal to 0.

Answer 13

I got undefined.

Answer 14

how did you get that answer

Answer 15

I just plugged in 1 for x.

Answer 16

you need to do more work than that since the limit does exist

Answer 17

Dont you take the derivative of the top and bottom functions?

Answer 18

\[\frac{\ln(x^2)}{x^2-1}=\frac{2\ln(x)}{x^2-1}\]

then use L'Hospital's rule

Answer 19

getting 2/x/2x

Answer 20

ok...now plug in a 1

Answer 21

Which gets 1.

Answer 22

yes

Answer 23

what about this?

Answer 24

you should post new question in a new post