Question

A tank of water holding 528 kL of water begins to empty at a rate of 10 kL/min. At the same time, another tank, which is empty, begins to fill at a rate of 14 kL/min. Let k represent the number of kiloliters of water and let t represent time in minutes. The system models this situation.



How long will it take for the tanks to hold equal amounts of water, and how much water will that be?



k = 528 – 10t

k = 14t



It will take minutes for both tanks to hold equal amounts of water. They will each hold kiloliters.

Answer 1

pls help i will give medel

Answer 2

please i reallllllllllllllllllllllllly need it

Answer 3

@mathmate

Answer 4

@mathmate

Answer 5

@SolomonZelman

Answer 6

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i would really apreciate it

Answer 7

pls

Answer 8

i really neeed it

Answer 9

They gave us the system which is nice :)\[\large\rm \color{royalblue}{k = 528 – 10t}\]\[\large\rm \color{orangered}{k = 14t}\]They will have the same amount of water when these k's are equal.

\[\large\rm \color{royalblue}{528-10t}=\color{orangered}{14t}\]Start by solving for t,
to figure out how much time passes for the tanks to have equal water.

Answer 10

than do i have my answer

Answer 11

Then you will have half of your answer, the time.

Answer 12

oh ok

Answer 13

it is 22

Answer 14

what about kiloliters

Answer 15

hello anybody there

Answer 16

:/

Answer 17

@mathowl609

Answer 18

@Zela101

Answer 19

anybody plsssssssssssssssssss

Answer 20

anybody pls will give medel

Answer 21

pls

Answer 22

any body i really need help really would apreciate it

Answer 23

@BigDreams

Answer 24

pls

Answer 25

@jim_thompson5910 this person needs help.

Answer 26

Hope you're free, take care @jim_thompson5910 x

Answer 27

t= 22 minutes is right. Now plug that value to any of the given equations to solve for the variable "k" .