How can I express logbx-(logby+logbz) as a single log?

Question

anonymous · Answer

When you subtract logarithmic expressions, you may divide their interior under one log. Contrarily, when you add logarithmic expressions, you may multiply their interior under one log. For example:
$$\log _{b} y+\log _{b} z = \log _{b} yz$$$$\log _{b} x-\log _{b} y = \log _{b}\frac{ x }{ y }$$Use these properties for your expression @kat50036

anonymous · Answer

but where is the Z?

anonymous · Answer

I merely showed you the properties. I was asking you to apply it to your expression so that you get a better understanding of the concept. Where should the z be? @kat50036

anonymous · Answer

$$\log_{b}x - (\log_{b}y + \log_{b}z)$$

anonymous · Answer

I thought it should maybe read logb x/yz?

anonymous · Answer

That's exactly right. Nice job.

anonymous · Answer

It is??? Thank you so much. Can I ask another one? About expanding?

anonymous · Answer

Sure go ahead and post it up. Don't forget to close this thread ^_^