Expand logb4x2y
2log(b) x -3( log(b) y + log(b) z . remember a log c = logc^a . log(b)x^2 -log(b)y^3 -log(b)z^3 . remember log a +log b = log(a*b),,,and log a -log b =log(a/b) . log(b) { x^2 / y^3 * z^3 } . checking, let b=10,,, a=1, ,, b=2,,,c=3 . original eqn = -2.33,,,,answer = -2.33,,,,,ok
that 's an example
So I'm thinking that maybe the answer would be 16logb+logby?
How exactly does your log expression look like? I'm suspecting that there are exponents that aren't represented properly.
Sorry, there should be an exponent of 2 after the 4x
Okay so like this?\[\log _{b}4x ^{2} y\]
yes
Okay, let's first separate our variables into two log expressions: \[\log _{b}4x ^{2} + \log _{b}y\] Then, we bring down our interior exponent as a coefficient. \[2\log _{b}4x + \log _{b}y\] And, this is as expanded as it gets.
Oh yeah, the two comes out front
Precisely
I wished I would have found this website when I first started my algebra class. My instructor is very good but I was still not getting it.
Then he wasn't good enough ^_^
Online algebra is much harder and its been MANY years since my last Algebra. I have one more, is that OK? I'll close this one.
Sure go ahead
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