Simplify the following problem using the distributive property: 4x + 6y + 3(x – y) – 5x. Show each step in your calculation and provide a reason why you can do each step. (Hint: You will use the number properties.) You will not get full credit if you do not give reasons.
Any ideas? :-)
no thats why im asking
You probably should get started. You'll probably have to get rid of the parentheses (properly) in order to combine those variables inside with those outside.
Do you recall the distributive property?
no
$$\huge a(b+c)=?$$
I mean, I've heard of it, just never used it
Complete the above equation please.
Are you still there?
oh, yea sorry, my dad was wanting me
Ok, np :-)
my internet is about to go out
$$\huge a(b+c) =?$$
The distributive property is what is known as a property of real numbers. Which means it can not be proven, but instead is accepted as true. What it states is that the "a" can be "distributed" as a multiplier over the b and c.
$$\Huge a(b+c)=ab+ac$$
Note that this pattern also holds with respect to subtraction $$\large a(b-c)=ab-ac$$
For your question: Simplify the following problem using the distributive property: $$\large 4x + 6y + 3(x – y) -5x$$ Applying the distributive property with respect to subtraction gives: $$\large 3(x-y) =3x-3y$$
$$\large 4x + 6y + 3(x – y) -5x=4x+6y+3x-3y-5x$$
Now use the definition of subtraction: $$\large a-b=a+(-b)$$ to replace the subtractions in your expression so far $$\large 4x+6y+3x-3y-5x = 4x+6y+3x+(-3y)+(-5x)$$
The next step is to use the commutative property of addition: $$\large a+b=b+a$$ to rearrange the expression so that all the terms with x in them such as 4x, 3x, and -5x are grouped together and the same for the terms with a y in them such as 6y and -3y. This will look like this: $$\large 4x+6y+3x+(-3y)+(-5x)=4x+3x+(-5x)+6y+(-3y)$$
Next, use the distributive property in the other direction: $$\large ba + ca = (b+c)a$$ $$\large (4+3-(5))x+(6+(-3))y = 2x+3y$$
h
Join our real-time social learning platform and learn together with your friends!