A bike has an inertia of 10.04 × 1237 mg•m3 and a mass of 7.2 × 1094 kg. Based on this, what is the bike rolling down's radius?
@Nnesha @pooja195
@Mashy
Do you know what is the expression for Moment of inertia of a solid sphere?
I=2/5 MR^2 correct?
that is correct. Mass is given to you and I is given to you so can't you just substitute and solve for R ?
i got R=93442.8, but i don't think thats right
No, that isn't.. Just crunch in the numbers carefully
what?
i got 9.74x1037=2/5(r)^2
and mass in there
it is 10 power 37, hope you plugged that in correctly and then took the square root!
ok ill try one more time and see what i get hold on please
do i have to use the m^2 in the moment of inertia??!
ok, this time i got R= 9.28, am i getting there? @Mashy
Nope
ok well I obviously need help, could i get some please???
Do step by step.. \[R^2 = \frac{5I}{2M} = \frac{5 \times 9.74 \times 10^{37}}{5.98 \times 10^{24}}\]
where'd you get the r^2
Crunch in the numbers and tell me what number pops out for R square?
In the moment of inertial equation buddy!
i got a really crazy number for my answer... for the second part of the equation only though i got: 8.14x10^64 :-(
I forgto to put a 2 in the denominator But I guess your calculator is broken, or you don't know how to use it :P
you are sort of rude... you are here to help not insult me on how your physics are superior to mine, you are a teacher not showing off what you can do. i asked for help, obviously i don't know how to do it or i wouldn't be asking for your help!
Oh, I am not trying to be rude, I am just not sure, how to show you to put numbers in the calculator
ok well I asked for help so obviously I am going to not know exactly how to do it, otherwise I wouldn't be asking. Sorry if me not knowing is annoying, but thats why Ia m here
Tell me what answer you get for R^2???
I am not sure because thats what I am trying to figure out. first i did 5×9.74×10375.98×1024 part of the equation and got an absurd answer of : 8.14x10^61 and i don't know what to do next
But that is wrong.. I forgot to put a 2 in the denominator and secondly the powers must be SUBTRACTED
oh ok, sorry!
\[R^2 = \frac{5 \times 9.74 \times 10^{37}}{2 \times 5.98 \times 10^{24}}\]
now i got 1.32 x10 ^54...
No it is \[4.07 \times 10^{13}\] :-/
oh, the two 10's simplify to one ok
so now what?
Now take the root
how do i do that again? sorry....I am in middle school but have to take this
Are you using a calculator?
yes
Is there a button which says \[\sqrt .\]
yes
That is the square root, but you got to make the ten power even. Can you try that?
do i hit square root button and then enter 4.07 x 10^13?
That depends on the type of calculator And before you do, please convert that number into an even power of 10, PLEASE, PLEASE DO THAT!!!
how? sorry
I ll just give you the answer. This planet is our home planet! So google the radius of earth, ,problem solved TADA!!!
please, i really do need help but this problem is really hard for me in only 7th grade but advanced
You need to watch some Khan Academy videos on math. You have math problem, not physics. You need to work on that.
please i need help just really with this problem :-( I'm jut going to keep asking on here for help so its not helping by leaving me
Parth, this is all yours!
:-(
Don't worry, Parth is awesome! :P
he left@
did you learn solving equations in math?
okay \[300 = 3 \times 10 ^2 = 30 \times 10^1 = 300 \times 10^0 = 0.3 \times 10^4 = 0.03 \times 10^5\] does that make sense?
oh pellet lol wait.. typo!!
yes
\[I = \frac{2}5 MR^2\]\[9.74\times 10^{37} = \frac{2}5 \times 5.98 \times 10^{24} \times R^2\]Can you solve this equation?
\[300 = 3 \times 10^2 = 0.3 \times 10^3\]
I subtract the exponents right? @Mashy @ParthKohli
yes@!!!
ok so far I have- 9.74x10^37=23.92xr^2
@Mashy
k
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