Question

someone tell me what this guy is trying to say PLEASE!

Answer 1

What is the simplified expression for 3 to the power of negative 4 multiplied by 2 to the power of 3 multiplied by 3 to the power of 2 whole over 2 to the power of 4 multiplied by 3 to the power of negative 3?

3 over 2
3 to the power of 2 over 2 to the power of 2
3 to the power of 2 over 2
2 to the power of 4 over 3

Answer 2

so your question is

\[\frac{3^{-4} \times 2^3 \times 3^2}{2^4\times 3^{-3}}\]

Answer 3

basically.

Answer 4

you can simplify the numerator by looking at the terms with the same base

remember when multiplying add the powers

\[m^a \times m^b = m^{a + b}\]

so apply this to the base 3 terms in the numerator

Answer 5

next the law for division is subtract the powers of the same base

\[\frac{m^a}{m^b} = m^{a - b}\]

you need to use these to laws to simplify

Answer 6

okay.

Answer 7

but idk how to, im so lost omfg. i have 2 more hrs of school after this smh.

Answer 8

ok... what is

\[3^{-4 + 2} = 3^?\]

what power do you get...?

Answer 9

is there some kind of special calculator needed for that?

Answer 10

nope... its just -4 + 2 = ?

Answer 11

-2

Answer 12

great so

\[3^{-4} \times 3^2 = 3^{-2}\]

so the problem is now

\[\frac{3^{-2} \times 2^3}{3^{-3} \times 2^4}\]

does that make sense..

Answer 13

i guess.

Answer 14

now you need to use the rule for division... which means you subtract the powers with the same base...

\[3^{-2} \div 3^{-3} = 3^{-2 -(-3)}\]

what would you get as an answer..?

and

\[2^3 \div 2^4 = 2^{3 - 4} \]

what do you think the power will be..?

Answer 15

if you have a scientific calculator, you can plug the information in the way it's written and you'll get the answer