Question

Verify by defination limit x approches infinty (x^2+4x+8)/(2x^3-3x^2+2) =1/2

Answer 1

\[\dfrac{(x^2+4x+8)}{(2x^3-3x^2+2)} \]

you sure it's not \[\dfrac{(x^\color{red}{3}+4x+8)}{(2x^3-3x^2+2)} \]

Answer 2

Yeah i am sure

Answer 3

Divide by the largest power on the denominator
lim x-->infinity(1/x+4/x^2+8/2-3/x+2/x^3)=0
you wont get 1/2 unless its x^3 in the numerator.

Answer 4

yes, Ab !!

Answer 5

thats correct

Answer 6

The limit as x approaches infinity of (x^2+4x+8)/(2x^3-3x^2+2) = 0