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prove: tan x/2 = the square root of 1-cosx/ 1+cosx
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\[\cos x = 2 \cos^2 \frac{x}2 - 1\]\[\cos x = 1 - 2\sin^2\frac{x}2\]Now find the values of \(1-\cos x \) and \(1 + \cos x\), then divide.
- got beaten to it lol!
thanks!!
did you get it?
yes i was just stuck on the second part and i have another problem that i am stuck on its prove: csc^2 x/2 = 2secx/secx -1
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@welshfella
yes i have done that already
sorry gtg right now
okay thanks anyway
im back
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heck gtg again
convert to sines and cosines 1 / sin^2 (x/2) = (2/ cos x) / [(1/ cos x) - 1]
now use Parthkholis second identity for cos x and plug it into the right side and simplify Its a bit messy but it will simplify to 1 / sin^2 (x/2)
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