okay so i need help with this one as well can someone please help me and walk me through it
i dont know how to do this at all..
We have the formula: \(\large F = \frac{9}{5}C + 32\) plug in 77 for f \(\large 77 = \frac{9}{5}C + 32\) subtract 32 from both sides: \(\large 77 - 32 = \frac{9}{5}C + 32 - 32\) \(\large 45 = \frac{9}{5}C\) divide both sides by \(\frac{9}{5}\) . \(\huge \frac{45}{\frac{9}{5}} = \frac{\frac{9}{5}}{\frac{9}{5}}\) \(\large \frac{45}{1} \times \frac{5}{9}\) c= 25
when dividing by 9/5 do you have to convert it to a decimal ? or how did you divide it?
what all you need to do was, apply that formula to convert, \( (°F - 32) x 5/9 = °C \) @akroayee and you can check your answer with ^ answer.
\((°F - 32) × 5/9 = °C\)
thanks :)
ny
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