Find the imaginary or real solutions of the equation by factoring X^3+64=0
Hi :) Welcome to openstudy! Any ideas on what the first step maybe?
No. I'm not sure how to factor numbers like this one
Ok well similar to difference of 2 squares we can start by subtract 64 from both sides \[\huge~\rm~x^3+64-63=0 -64\]
Now we have \[\huge~\rm~\bf~x^3=-64\] Now you would take the cube root are you familiar with how to do that?
Of I had a calculator
Or without a calculator
That's one good approach c: It looks like they want us to solve this one by factoring though. Recall your `Sum of Cubes` Formula:\[\large\rm a^3+b^3=(a+b)(a^2-ab+b^2)\]
I didn't see they wanted it by factoring sorry im not familiar with that method @zepdrix seems to be good at it perhaps he can continue with the problem :-)
64 is actually a perfect cube, 64 = 4*4*4 So we can rewrite our expression,\[\large\rm x^3+64\]as\[\large\rm x^3+4^3\]From there, we can apply our `Sum of Cubes` Formula
Okay, so I find the cube, and then re-write it.
Applying the formula gives us this,\[\large\rm x^3+4^3=(x+4)(x^2-4x+4^2)\] I'll give you a moment to digest that, look back at the formula involving a and b for reference.
I don't get how to use the formula. I've never seen it in my life
Have you ever heard the acronym SOAP? It's often used as a nice easy way to remember this formula.
No I have not. My math teacher doesn't put any description in his online lessons. He kind of just expects us to understand everything
|dw:1450648338054:dw|This is where our SOAP acronym comes from.
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