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Geometry 11 Online
OpenStudy (nicoleg7):

does anyone have geometry on flvs?

OpenStudy (alexandervonhumboldt2):

Please post your question.

OpenStudy (nicoleg7):

Prove the Pythagorean Theorem using similar triangles. The Pythagorean Theorem states that in a right triangle, the sum of the squares of the lengths of the legs of the triangle equals the squared length of the hypotenuse. Be sure to create and name the appropriate geometric figures.

OpenStudy (alexandervonhumboldt2):

and you need a student from flvs geometry to do that? rofl

OpenStudy (nicoleg7):

well I was just asking to see if anyone from flvs had don that recently but I mean anyone can help me if they want

OpenStudy (alexandervonhumboldt2):

|dw:1450592758802:dw|

OpenStudy (alexandervonhumboldt2):

triangle AHC and ABC are simillar because because they both have a right angle , and they share the angle A.

OpenStudy (nicoleg7):

would that be all I would have to write because this is something I have to write and I am not quite sure how I would put the drawing into word form since I can't draw it.

OpenStudy (alexandervonhumboldt2):

thus: \[\huge\bf\frac{ BC }{ AB}=\frac{ BH }{ BC }\] \[\huge\bf \frac{ AC }{ AB }=\frac{ AH }{ AC }\]

OpenStudy (alexandervonhumboldt2):

we get that \[\huge\bf BC^2=AB*BH\] \[\huge\rm AC^2=AB*AH\] add: \[\large\mathbb {BC^2+AC^2=AB*BH+AB*AH=AB*(AH+BH)=AB^2}\]

OpenStudy (alexandervonhumboldt2):

it is a little confusing. Other types of proofs are easier

OpenStudy (nicoleg7):

yeah it is confusing could you please help me tho better understand in a simpler way or alteast tell me how to arrange this from the beginning to end.

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