Question

Given the position function, s of t equals t cubed divided by 3 minus 12 times t squared divided by 2 plus 36 times t , between t = 0 and t = 15, where s is given in feet and t is measured in seconds, find the interval in seconds where the particle is moving to the right.

Answer 1

\[s(t) = \frac{ t^3 }{ 3-12t^2+36t }\] this?

Answer 2

yes

Answer 3

wait no it's not..

Answer 4

\[s(t) = \frac{ t^3 }{ 3 }-\frac{ 12t^2 }{ 2 }+36t\]

Answer 5

Yeah ok there we go

Answer 6

yeah sorry

Answer 7

Do you know calculus?

Answer 8

Finding the derivative will give you the velocity

Answer 9

yes somewhat

Answer 10

Can you find the derivative of your function

Answer 11

(x-6)^2?

Answer 12

How did you get that

Answer 13

Try the power rule, mhm do you know what derivatives are?