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What is the solution to the system of equations represented by the two equations? y=2/3x y=-2/3x+4
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so the first step is.....
@K12girlohva
anybody need help
put both y equal to each other
-2/3 x +4 =2/3 x
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solution 3xy=2...........i y(3x+4)=-2......ii 3xy+4y=-2.......iii substute eqn (i) into eqn (iii) 2+4y=-2 4y=-4 y=-1 from eqn (i) 3xy=2 but y=-1 3x(-1)=2 -3x=2 x=-2/3 the values of (x,y)=(-2/3,-1)
hey olivia did u get it
i cant type a fraction in the answer box :(
add eqs then 2y =4 y=2 and 2=2/3 x 6=2x x=3 ans (3,2)
ight thanks
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i do not think if it is correct @moh since the variables x and y they come together as product...only substitution can save us can u solve it from the starting point
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