Question

which of the following is not a perfect square?
A. 4
B. 300
C. 81
D. 36

Answer 1

300

Answer 2

\(\color{#0000ff }{ \displaystyle 16=4\cdot 4=4^2 }\)
So, \(16\) is a perfect square, because you
are multiplying a number \(4\) times itself
(also \(4\)) to obtain \(16\)\(\bf .\)

\(\color{#0000ff }{ \displaystyle 25=5\cdot 5=5^2 }\)
So, \(25\) is a perfect square, because you
are multiplying a number \(5\) times itself
(also \(5\)) to obtain \(25\)\(\bf .\)

\(\color{#0000ff }{ \displaystyle 1=1\cdot 1=1^2 }\)
So, \(1\) is a perfect square, because you
are multiplying a number \(1\) times itself
(also \(1\)) to obtain \(1\)\(\bf .\)

\(\color{#ff0000 }{ \displaystyle 0=0\cdot 0=0^2 }\)
That is true, BUT... THIS IS AN EXCEPTION, \(0\) IS NOT A PERFECT SQUARE!

\(\color{#0000ff }{ \displaystyle 9=3\cdot 3=3^2 }\)
So, \(9\) is a perfect square, because you
are multiplying a number \(3\) times itself
(also \(3\)) to obtain \(9\)\(\bf .\)

Answer 3

soo... 81?

Answer 4

81 = 9 × 9 = 9\(^2\)

Answer 5

So \(81\) is a perfect square

Answer 6

then 300

Answer 7

yes, 300 is NOT a perfect square.

Answer 8

You can make the following definition \(\small(\)below\(\small) \).
Suppose there is a natural number \(\color{#0000ff }{ \displaystyle \ell }\).

So, if \(\color{#0000ff }{ \displaystyle \ell \times \ell=x}\)
Then, \(\color{#0000ff }{ \displaystyle x}\) is a perfect square.

Answer 9

medal plz @LittleHeron #Being_selfish

Answer 10

The main thing is the learning, not medals...

According to the policy, you should not:
- Give direct answers
- Ask for medals explicitely.

Answer 11

hmmm

Answer 12

@littleheron wud give me one if he wants to