Question

Can anyone help me with this really easy question?  

Answer 1

I can't seem to load the picture could you put it in text form and maybe do a screen shot?

Answer 2

Ok can you screen shot it?

Answer 3

Also what is the math subject?

Answer 4

Nice I can open that one don't know why the other one wouldn't work.

Answer 5

It's not clear to me that ADC is a right angle. Is it?

Answer 6

Yes it does seem that way I am sorry my computer is being so slow.

Answer 7

No, not ACD, but ADC. This information is NOT in your fist picture, but it IS in your second picture. So, \(\overline{AD}\) is an altitude of \(\triangle{ACB}\). Does that help?

Answer 8

I am helping. I am not giving. YOU must do more thinking and less panicking.

We know something about the Altitude of a Right Triangle. It's length is the geometric mean between the two pieces of the Hypotenuse that it has defined. This can be stated a couple of ways, but most conveniently might be the ratio version:

\(\dfrac{m\overline{AD}}{m\overline{BD}} = \dfrac{m\overline{DC}}{m\overline{AD}}\)

Answer 9

The task is to find the right facts and put them together for a solution. We are now dumping facts. Putting them together, yet?

Answer 10

AD is perpendicular to BC right?

Answer 11

Yes, it's in the second attachment, but not the first.

Answer 12

ADC and ADB are right angles.

Answer 13

What kind of theorems have you been studying?

Answer 14

It's not actually clear to me what is wanted. It feels like we are using the Pythagorean Theorem to prove the Pythagorean Theorem.

Answer 15

Have you used any of the geometric means theorems?

Answer 16

We'd need to have AB^2 + AC^2 on one side of the equation right?

Answer 17

So which can you eliminate?

Answer 18

You tell me. It requires thinking. It will not jump out and bite you.

Answer 19

sorry i can't help you on this one. i haven't done math in a while so i don't exactly remember the best way to work out this problem.

Answer 20

So we know it will be C or D right

Answer 21

Using the theorems for the similar triangles we see here in the diagram lets see if we can get an equation that equals BC^2 something.

Answer 22

No think again. We are cross multiplying can we do something with those other two?

Answer 23

easy???

Answer 24

No you cannot eliminate the AC^2