Question

Brian has a bag that contains 14 red marbles and 12 yellow marbles. He selects a marble at random, and then, without replacing the first one, selects another marble at random.

What is the probability that Brian selects a red marble and then a yellow marble? Round your answer to the nearest percent.

P(red and yellow)

Answer 1

26%

Answer 2

46%

Answer 3

The correct answer is 26% because 14/26 * 12/25 = 0.25846154.

Answer 4

26%

Answer 5

probability to get a red marble is 14/26
whereas the probability to get an yellow marble is 12/25
I supposed to get a red marble for first.
So the requested probability is:
\[\huge p = \frac{{14}}{{26}} \times \frac{{12}}{{25}} \times 100 = ...?\]

Answer 6

so 26%

Answer 7

yes! We get \(25.8 \%\) which can be rounded to \(26\%\)

Answer 8

k

Answer 9

:)