how do you graph the line y=2?

Question

hakunamatata34 · Answer

I would think you would put 2 on the y-intercept then got down one across 2 and so on

calculusxy · Answer

It's a horizontal line:
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hakunamatata34 · Answer

am I right calculusxy

a_ryba · Answer

So, how do I graph that line based off of a transformation?

calculusxy · Answer

Transformation from what?

hakunamatata34 · Answer

I would think put 2 on the y-intercept then go down 2 and across 1

a_ryba · Answer

a point of reflection in the origin, which I just did

a_ryba · Answer

and which way across; to the left, or right?

calculusxy · Answer

@hakunamatata34 What you are talking about would be the line of the equation: 
$y = -2x + 2$ which is different from saying $y = 2$

calculusxy · Answer

@A_ryba You would just be going up by 2 units.

a_ryba · Answer

so from each point, just move up two?

hakunamatata34 · Answer

oh lol im confused on this question sorry

calculusxy · Answer

Since you are simply saying y = 2, that would be a horizontal line because that line is going across the y-axis. You don't have any slope therefore you don't need to be going up by 2 consistently. If you were you would have started from, let's say the y-int of 2 (0,2) and then move up by 2 and then to the right 1 unit (4, 1). You would have the line going an infinite amount of spaces to the left and the right (does not matter how many units) with simply y = 2.

a_ryba · Answer

I do not understand a word you just said

calculusxy · Answer

attachment

calculusxy · Answer

Take a look at that. Do you see how that line just hits one point on the y-axis?

a_ryba · Answer

yeah

calculusxy · Answer

And then it continues to go in left and right?

a_ryba · Answer

what does

calculusxy · Answer

The line

a_ryba · Answer

the one you showed me? Yes

calculusxy · Answer

So that's what I was saying when the line will go infinite amount of spaces to the left and right.

calculusxy · Answer

The transformation from the origin is that you only move 2 units up and just draw a line that runs horizontally from that point (0,2).

a_ryba · Answer

oh?

a_ryba · Answer

I have one more question from my sheet that I don't now how to do: 

A) On the accompanying grid, graph the equation 2y=2x squared -4 in the interval -3 is < (with the line under it) x < (with the line under it) 3 and label it a. 
b) On the same grid, sketch the image of a under T5,-2 after the r x-axis and label it b.