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Chemistry 12 Online
OpenStudy (anonymous):

1. Write the equilibrium constant expression for the third ionization of phosphoric acid (H3PO4) in water.

OpenStudy (anonymous):

@emmynimmy @Hayhayz @byronichero @xlovely_Lizardx @Zarkon @hperez777 @timo86m

OpenStudy (anonymous):

imquerty, any idea?

imqwerty (imqwerty):

:) its imqwerty but you can call me that too :D okay so we have \(H_3PO_4\) do you know the stepwise ionization reactions of this acid? :)

imqwerty (imqwerty):

i can tell you in case you forgot :)

imqwerty (imqwerty):

@CreatingMyself u there? (:

OpenStudy (anonymous):

YesYes I'm here!

OpenStudy (anonymous):

And no I only know the first ionization :(

imqwerty (imqwerty):

okay so these are the three reactions in sequential order- http://prntscr.com/9h0ah5

imqwerty (imqwerty):

so this how you do this question- 1st wee write the 3rd ionization reaction of \(H_3PO_4\) in water-> \(H_3PO_4 ^{-2}\)\(_{(aq)}\)---------->\(H^+ _{(aq)}~~+~~PO_4 ^-3_{(aq)}\) the ionic concentration is given like this-> ionic concentration =\(\Large \frac{[Products]}{[Reactants]}\) so in out case we will have this-> ionic concentration=\(\Large \frac{[H^+][PO_4 ^-3]}{[HPO_4 ^{-2}]}\) and this value comes equal to-> \(4.8 \times 10^{-13}\)

OpenStudy (anonymous):

Ahhhhh!! How did you calculate the ionic concentration though? what values did you substitute in place of the reactants and products?

imqwerty (imqwerty):

well thats a general value that i remember :) i wrote that just for info you don't have enough data in this problem to calculate that so in you case the answer is just this-> ionic concentration=\(\Large \frac{[H^+][PO_4 ^-3]}{[HPO_4 ^{-2}]}\)

OpenStudy (anonymous):

Ah so my answer ends up as Ka=(that equation)

OpenStudy (anonymous):

Thank you! I have 3 more questions if you wouldn't mind answering them, in separate open questions of course. More medals i can give ya!

OpenStudy (anonymous):

oops not Ka Ka is acid equilibrium

imqwerty (imqwerty):

yeah :) i am really sorry but i gtg now x-x i have a class and i got few hours to sleep

OpenStudy (anonymous):

Well thanks anyway man! Medal!

imqwerty (imqwerty):

lol np (; buh bye :D

OpenStudy (anonymous):

get some sleep!!

imqwerty (imqwerty):

lol i really must go but its really difficult to log off x-x os is kinda addicting

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