I need some massive Calc. help!
The function h is given by h(x)=cos(kx)[f(x)]+sin(x) for all real numbers, where k is a constant. Find h ′(x) and write an equation for the line tangent to the graph of h at x=0.
This is the information give: The twice–differentiable function f is defined for all real numbers and satisfies the following conditions: f(0)=3 f ′(0)=5 f ‘’(0)=7
I know I have to go from here: lim h->0 (cos(k(x+h))[f(x+h)+sin(x+h)] - cos(k(x))[f(x)+sin(x)]/(h))
Or rather: ((cos(k(x+h))[f(x+h)]+sin(x+h)) - (cos(kx)[f(x)]+sin(x)))/h
why do you have to do that? just use the product rule
Oh! So the derivative of the constituents multiplied to get the whole derivative?
\[\frac{d}{dx}[f(x) * g(x)] = f'(x) g(x) + f(x) g'(x)\]right?
I see. Yes thank you! I need to review these things.
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