Lagrange Multiplier Million Dollar question. Anybody please Use the method of Lagrange multipliers to find the max and min values of g(s,t)=t^2e^s given that s^2+t^2=3 . How are we assured that these extreme values exist?
I have one critical point
Are you looking for some real analysis kindof existence proof.. or just some intuition ?
real Analysis please
Then what is lagrange multiplier doing here ?
\[(1, \sqrt{2}) (1 -\sqrt{2})\]
Pardon?
Lagrange multiplier method is just one way to find the extrema. It has nothing to do with the existence part right ?
yes I know, and from the Extreme Value Theorem tells us that minimums and maximums will always exist.
I think my Instructor wants me to graph, and show that the max and min exist.
But I am only getting max and no mean from the two critical point \[(1 \sqrt{2}) (1 \sqrt{-2})\] and f gives me 2e for both points
Is this max or min point? How can I tell.
tried to graph but looks tedious.
and s also =-3 which has not value for t.
hello.
Lagrange multiplier doesn't give you information about the type of extrema. You will need to use hessian matrix for that
Hessian? did not cover that
Then you will need to find the type of extrema by some other means
but To determine if we have maximums or minimums we just need to plug these into the function. critical points
Yes that will do
yes that that is what I did.
Can you determine the max and min please?
I got 2e for boths critical points
Are the two points bot max? what about min. could it be that these function doest not have a min.
I am getting 6 critical points http://www.wolframalpha.com/input/?i=solve+t%5E2e%5Es%3D2%5Clambda*s%2C+2te%5Es+%3D+2%5Clambda*t%2C+s%5E2%2Bt%5E2%3D3
please look closely at x=-3 the value for t -root
\((\pm \sqrt{3}, 0 )\) give you minimum \((1,\pm \sqrt{2})\) give you maximum and yeah other two critical points are not real
I figured that simply by evaluating g(s,t) at those values, as you said earlier
And the last part of the question how are we sure that these values exist?
How did you get the second critical point pmsruareroont of 3.
Please go through this for a proof of lagrange multipliers method http://ocw.mit.edu/courses/mathematics/18-02sc-multivariable-calculus-fall-2010/2.-partial-derivatives/part-c-lagrange-multipliers-and-constrained-differentials/session-40-proof-of-lagrange-multipliers/MIT18_02SC_notes_22.pdf
I got those critical points by solving : http://www.wolframalpha.com/input/?i=solve+t%5E2e%5Es%3D2%5Clambda*s%2C+2te%5Es+%3D+2%5Clambda*t%2C+s%5E2%2Bt%5E2%3D3
\(\sqrt{3} = 1.73205\ldots\)
geometrical look at this problem is helpful. z= f (x, y)= x + 2y is a plane passing through the origin. The constraint x^2 +y ^2 + 5 is a right circular cylinder. The maximum value of f (x, y)= x+ 2y exists and occurs at the highest point on the curve of intersection of the cylinder and the plane. Example from my note. I do not need proof of lagrange to know if the values exist or not. i need like a geometrical look. @ganeshie8 and thank you so much. really apprecaite.
geometric look?
http://www.wolframalpha.com/input/?i=graph+t%5E2e%5Es form here I can see the two values of the max and min How can I plot this on paper. @ganeshie8 thank you.
@mathmale can you please look at this lagrange multiplier example. I get everything except the last part of the question. "How are we sure these extreme values exist" I know by the extreme value theorem a max and min WILL ALWAYS EXIST. Thank you
What will be the argument here? I could not sketch of the graph of function but from wolfram I can see that the function has two max value and one minimum value. http://www.wolframalpha.com/input/?i=graph+t%5E2e%5Es @mathmale Thanks
@mathmale help please.
I'd love to help, but it's been several years since I last encountered Lagrange Multipliers. Frankly, I don't remember enough about them to help you. Thanks for calling on me, however. Good luck!
Its Ok Thanks
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