Ask your own question, for FREE!
Mathematics 7 Online
Parth (parthkohli):

Gases

Parth (parthkohli):

The equation of state of a gas is given by\[V = \frac{RT}p - \frac{b}T\]where \(R\) is the gas constant and \(b\) is another constant parameter. The specific heat at constant pressure \(C_P\) and the specific heat at constant volume \(C_V\) for the gas is related by the relation \(C_P - C_V = \cdots\)

Parth (parthkohli):

\[C_m = \frac{dQ}{dT} = \frac{dU + dw}{dT} = \frac{dU}{dT}+p\frac{dV}{dT}\]\[C_V = \frac{dU}{dT} ~\rm since ~dV=0.\]\[\Rightarrow C_m =C_V + p\frac{dV}{dT}\]

Parth (parthkohli):

\[\frac{dV}{dT} = \frac{R}p+\frac{b}{T^2}\]\[p\frac{dV}{dT}=R+\frac{pb}{T^2}=C_P-C_V \]

Parth (parthkohli):

where did I go wrong

Parth (parthkohli):

I've treated \(p\) as a constant parameter which it is.

Parth (parthkohli):

http://imgur.com/Srqgwer

Parth (parthkohli):

(C) is pretty close to my answer except there's a squared term.

ganeshie8 (ganeshie8):

yeah removing that 2 in the exponent matches with your answer

Parth (parthkohli):

the problem is we can't dimensionally verify this either, because the terms multiplied to \(R\) are dimensionless.

Parth (parthkohli):

Hey ganeshie is it possible to use the given equation of state and manipulate the answer?

Parth (parthkohli):

Certainly got my definitions wrong somewhere along the way... >_<

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!