In ΔABC shown below, BD over BA equals BE over BC: The following flowchart proof with missing statements and reasons proves that if a line intersects two sides of a triangle and divides these sides proportionally, the line is parallel to the third side: Which reason can be used to fill in the numbered blank space? A) 1. ∠BDE ≅ ∠BAC 2. Corresponding Angles Postulate B) 1. ∠BDE ≅ ∠BAC 2. Corresponding Parts of Similar Triangles C) 1. ∠BDE ≅ ∠BCA 2. Alternate Exterior Theorem D) 1. ∠BDE ≅ ∠BCA 2. Corresponding Parts of Similar Triangles
@Kirby123
B=B by the reflexive property
ok
1. ΔABC ~ ΔDBE 2. Side-Angle-Side Similarity Postulate
ok
1. ∠ A ≅ ∠ A 2. Reflexive Property of Equality 1. ∠ A ≅ ∠ B 2. Corresponding Parts of Similar Triangles 1. ∠ A ≅ ∠ B 2. Corresponding Angles Postulate 1. ∠ B ≅ ∠ B 2. Reflexive Property of Equality
4. ∠ A ≅ ∠ C; Isosceles Triangle Theorem 5. ΔBDE ~ ΔBAC; Angle-Angle (AA) Similarity Postulate
ok, thank you!
the answer is B =B
thank you
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