Suppose that the functions f and g are defined for all real numbers x as follows.
f(x) = x + 2
g(x) = 4x + 3
Write the expressions for (f+g)(x) and (f-g)(x) and evaluate (f*g)(1).
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OpenStudy (jchick):
Any idea how to start?
OpenStudy (anonymous):
I am not really sure, I kind of just need someone to walk me through this problem. I am having a hard time with it
OpenStudy (jchick):
Ok so have you done any so far?
OpenStudy (anonymous):
yes
OpenStudy (jchick):
Ok please post what you have done.
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OpenStudy (anonymous):
Oh you meant on this problem?
OpenStudy (jchick):
Yes
OpenStudy (anonymous):
I haven't done anything on this problem. Sorry for the confusion
OpenStudy (jchick):
Ok so here is what we are looking at.
OpenStudy (jchick):
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OpenStudy (anonymous):
So, x+2 + 4x + 3
OpenStudy (jchick):
We need to combine like terms!
OpenStudy (anonymous):
4x^2 + 5 ?
OpenStudy (jchick):
So combine the x and the constants.
OpenStudy (jchick):
Not quite look at 4x^2 again you are going to add one.
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OpenStudy (anonymous):
Is it 4x^3 or add one to four
OpenStudy (jchick):
Add one to the four
OpenStudy (jchick):
So it will become 5x.
OpenStudy (jchick):
Can we combine our constants?
OpenStudy (anonymous):
That would be 5 as well
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OpenStudy (jchick):
Yes so our answer is 5x + 5 would you like to try the other one?
OpenStudy (anonymous):
And that's the expression right?
OpenStudy (jchick):
We still have another one to solve for.
OpenStudy (jchick):
OpenStudy (anonymous):
Okay
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OpenStudy (anonymous):
So x + 2 = 4x + 3
OpenStudy (anonymous):
Do we have to change the addition signs or does it stay the same?
OpenStudy (jchick):
All of the ones in the second will be minus.
OpenStudy (anonymous):
x - 2 - 4x -3?
OpenStudy (jchick):
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OpenStudy (jchick):
I think I might have said it a little confusingly.
OpenStudy (jchick):
So now we need to combine like terms.
OpenStudy (anonymous):
-3x?
OpenStudy (anonymous):
for the x terms?
OpenStudy (jchick):
Yes that is correct
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OpenStudy (jchick):
Now for the constants?
OpenStudy (anonymous):
2-3 = -1
OpenStudy (anonymous):
so -3x -1
OpenStudy (jchick):
Correct!
OpenStudy (jchick):
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OpenStudy (jchick):
So we actually have one more thing to solve for.
OpenStudy (jchick):
Sorry didn't notice until now.
OpenStudy (anonymous):
great! okay so the next one
OpenStudy (jchick):
Ok so
OpenStudy (jchick):
Here is what we are looking at what is the one where the x usually is?
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OpenStudy (jchick):
So what will we do with the 1?
OpenStudy (anonymous):
we multiply?
OpenStudy (jchick):
No we will use that instead of the x in (f)x
OpenStudy (jchick):
Sorry f(x)
OpenStudy (anonymous):
so f(1) = (4(1) + 3) * g(1) = (1 +2)
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OpenStudy (jchick):
OpenStudy (anonymous):
g(1) = 8?
OpenStudy (anonymous):
or is it 7?
OpenStudy (anonymous):
and then 7*3 = 21
OpenStudy (jchick):
With PEMDAS it would be what?
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OpenStudy (jchick):
Now we need to substitute it into the equation.
OpenStudy (anonymous):
Well I 4(1) + 3, which is 4(1) = 4 and then 4 +3 is 7?
OpenStudy (jchick):
Correct!
OpenStudy (anonymous):
so the answer is 21 right?
OpenStudy (jchick):
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OpenStudy (anonymous):
3*7 = 21
OpenStudy (anonymous):
Is that right?
OpenStudy (jchick):
Yes!
OpenStudy (anonymous):
Thanks! Do you think you might be able to help me with one more question?
OpenStudy (jchick):
Sure!
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OpenStudy (anonymous):
@jchick
OpenStudy (jchick):
Sorry I didn't get a reply for a few min so I left the page I will look.
OpenStudy (anonymous):
Okay!
OpenStudy (jchick):
I see the graph but where is the question?
OpenStudy (anonymous):
I am going to type it now!
Use the graph of the function f below to find the following.
All values at which f has a local minimum
All local minimum values of f
If there is more than one answer, separate them with commas
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OpenStudy (anonymous):
@jchick
OpenStudy (jchick):
Ok sorry my computer wasn't letting me type anything.
OpenStudy (jchick):
Ok so they are looking for x. They want you to find the f(x).
OpenStudy (anonymous):
SO how do I do that?
OpenStudy (jchick):
Hang on I am drawing a blank here.
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OpenStudy (anonymous):
This is what the question is looking for, all values at which f has a local minimum. do you think you can help me solve that first?
OpenStudy (jchick):
I believe that your local minimum is -3
OpenStudy (jchick):
You can find the local minimum by looking to see where the second to lowest point on the graph is.
OpenStudy (anonymous):
Ok so your right it's -3?
OpenStudy (anonymous):
what about the second question? how would i find that?
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OpenStudy (anonymous):
all local minimum values of f?
OpenStudy (jchick):
What second equation?
OpenStudy (jchick):
Ok
OpenStudy (jchick):
I do not see F mentioned anywhere in your graph.
OpenStudy (jchick):
Oh wait I see it is a graph of F
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OpenStudy (jchick):
You have an absolute minimum but I didn't know you could have more than one local minimum.