The graph shows the quantity of each piece in a toy building kit. If one piece is missing, what is the probability that it is a blue piece with four holes?
A. about 11% B. about 23% C. about 33% D. about 67%
"one peace is missing" (for our problem) is equivalent to saying "one peace is selected"
How many pieces are there altogether? How many of them are "blue" with "4 holes"?
55 pieces 12 are blue with 4 holes
12 are blue, but not all are with 4 holes
How many of these blue peaces have 4 holes (not 2 holes, but 4 holes)
?
and I think the total amount of piece is also incorrect.
9+8+12+6=35
(not 55)
yes it's wrong I didn't understand
So, you have 4 "desired" peaces (blue, with 4 holes) out of 35 peaces (altogether).
11%
And the chance to select a blue peace (or to have the blue peace missing - which is same in the context of the problem), is.... yes, about 11%
But Solomon, you are only including those with 4 holes. What about the 20 pieces with only 2 holes that are also in the kit?
Thank you very much! Can you help me with some few more?
35 - all peaces 4 - blue with 4 holes (the probability of which to be selected we want to find)
LegendarySadist, I doubt that I made an error....
No, there are 55 pieces. There are 35 pieces that have 4 holes and 20 with 2 holes.
two columns in each column, every column?
For the blue pieces, 12 have 4 holes and 8 have two holes. It is shown in the graph that there are different amounts of pieces with 2 or 4 holes for every color.
No, it is 12 overall... that is how they drew the Histogram with frequencies, or else they would need two histograms.
Then the green line being at 8 represents what?
I would say Solomon is right on this one
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